Answer:
Adult tickets =125
Child tickets = 128
Step-by-step explanation:
Let the number of adult and children tickets sold be x and y respectively
So that
x+y= 253--------1
Since total sales/receipt is $2,771
And given that tickets for a dance recital cost $15 for adults and $7 for children hence
15x+7y= 2771-------2
Solving equation 1 and 2 simultaneously we have
x+y= 253---------------1
15x+7y= 2771----------2
Let us multiply equation 1 by 15 to get equation 3 to eliminate x and subtract equation 2 from 3
15x+15y=3795---------3
-{15x+7y= 2771----------2
0+8y=1024
8y= 1024
y= 1024/8
y= 128 tickets
So solve for x let us put y= 128 in equation 1
x+ 128=253
x=253-128
x= 125 tickets
Answer: C
Step-by-step explanation:
Simplify the expression to 2^1/4
Now transform the expression using a^m/n = n root a raised to a power of m.
And that's how you get your answer.
Answer:
14
Step-by-step explanation:
Caitlin buys twice as many apples as oranges.

Apples cost 0.25 and Oranges cost 0.30, we have a maximum of 5 to spend.


If you would like to solve the equation 3 * (3 * x - 1) + 2 * (3 - x) = 0, you can calculate this using the following steps:
3 * (3 * x - 1) + 2 * (3 - x) = 0
3 * 3 * x - 3 * 1 + 2 * 3 - 2 * x = 0
9 * x - 3 + 6 - 2 * x = 0
7 * x + 3 = 0
7 * x = - 3 /7
x = - 3/7
The correct result would be - 3/7.
Answer:
Pattern B
<h3>
Explain: </h3>
A quadratic relationship is characterized by constant second differences.
<em><u>Pattern A
</u></em>
Sequence: 0, 2, 4, 6
First Differences: 2, 2, 2 . . . . constant indicates a 1st-degree (linear, arithmetic) sequence
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<em><u>Pattern B</u></em>
Sequence: 1, 2, 5, 10
First Differences: 1, 3, 5
Second Differences: 2, 2 . . . . constant indicates a 2nd-degree (quadratic) sequence
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<em><u>Pattern C</u></em>
Sequence: 1, 3, 9, 27
First Differences: 2, 6, 18
Second Differences: 4, 12 . . . . each set of differences has a common ratio, indicating an exponential (geometric) sequence
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Pattern B shows a geometric relationship between step number and dot count.