Divide 405 in the ratio 4:11

A puppeteer is making a triangular hat for a puppet. If two of the three angles of

Burka [1]

Answer:

The triangle is an isosceles triangle and the measure of the third angle is 120°

Step-by-step explanation:

the other nd 2 angles in the triangle both measures 30 degrees, the triangle angle sum theorem states that all the angles in a triangle add up to 180 degrees. Add the first two angles together and subtract it from 180. That's

180 - 60 and it equals 120

5 0

3 years ago

A particle moves according to a law of motion s = f(t), t ? 0, where t is measured in seconds and s in feet.

Usimov [2.4K]

Answer:

a) $\frac{ds}{dt}= v(t) = 3t^2 -18t +15$

b) $v(t=3) = 3(3)^2 -18(3) +15=-12$

c) $t =1s, t=5s$

d) $[0,1) \cup (5,\infty)$

e) $D = [1 -9 +15] +[(5^3 -9* (5^2)+ 15*5)-(1-9+15)]+ [(6^3 -9(6)^2 +15*6)-(5^3 -9(5)^2 +15*5)] =7+ |32|+7 =46$

And we take the absolute value on the middle integral because the distance can't be negative.

f) $a(t) = \frac{dv}{dt}= 6t -18$

g) The particle is speeding up $(1,3) \cup (5,\infty)$

And would be slowing down from $[0,1) \cup (3,5)$

Step-by-step explanation:

For this case we have the following function given:

$f(t) = s = t^3 -9t^2 +15 t$

Part a: Find the velocity at time t.

For this case we just need to take the derivate of the position function respect to t like this:

$\frac{ds}{dt}= v(t) = 3t^2 -18t +15$

Part b: What is the velocity after 3 s?

For this case we just need to replace t=3 s into the velocity equation and we got:

$v(t=3) = 3(3)^2 -18(3) +15=-12$

Part c: When is the particle at rest?

The particle would be at rest when the velocity would be 0 so we need to solve the following equation:

$3t^2 -18 t +15 =0$

We can divide both sides of the equation by 3 and we got:

$t^2 -6t +5=0$

And if we factorize we need to find two numbers that added gives -6 and multiplied 5, so we got:

$(t-5)*(t-1) =0$

And for this case we got $t =1s, t=5s$

Part d: When is the particle moving in the positive direction? (Enter your answer in interval notation.)

For this case the particle is moving in the positive direction when the velocity is higher than 0:

$t^2 -6t +5 >0$

$(t-5) *(t-1)>0$

So then the intervals positive are $[0,1) \cup (5,\infty)$

Part e: Find the total distance traveled during the first 6 s.

We can calculate the total distance with the following integral:

$D= \int_{0}^1 3t^2 -18t +15 dt + |\int_{1}^5 3t^2 -18t +15 dt| +\int_{5}^6 3t^2 -18t +15 dt= t^3 -9t^2 +15 t \Big|_0^1 + t^3 -9t^2 +15 t \Big|_1^5 + t^3 -9t^2 +15 t \Big|_5^6$

And if we replace we got:

$D = [1 -9 +15] +[(5^3 -9* (5^2)+ 15*5)-(1-9+15)]+ [(6^3 -9(6)^2 +15*6)-(5^3 -9(5)^2 +15*5)] =7+ |32|+7 =46$

And we take the absolute value on the middle integral because the distance can't be negative.

Part f: Find the acceleration at time t.

For this case we ust need to take the derivate of the velocity respect to the time like this:

$a(t) = \frac{dv}{dt}= 6t -18$

Part g and h

The particle is speeding up $(1,3) \cup (5,\infty)$

And would be slowing down from $[0,1) \cup (3,5)$

5 0

3 years ago

Find the value of m < 7 .

lesya [120]

Answer:

B

Step-by-step explanation:

the exterior angle of a triangle is equal to the sum of the 2 opposite interior angles.

∠ FES is an exterior angle of the triangle , then

57° + ∠ F = 142° ( subtract 57° from both sides )

∠ F = 85°

7 0

2 years ago

Read 2 more answers

Find the range of values of x for which 2x2 – 5x + 2 > 0

Alchen [17]

Answer:

x < 1/2 and x>2

Step-by-step explanation:

first solve the eqn,

2x2 -5x +2 = 2x2 -4x -x +2 = 2x(x-2) - 1(x-2) = (2x-1)(x-2)

since the questions asks for >,

x < 1/2 and x>2

if the question had asked for <,

1/2<x<2

7 0

3 years ago

35 is what percent of 150? Enter your answer in decimal form to the nearest hundreth.

Sophie [7]

Answer:

23.33%

Step-by-step explanation:

Solution for 35 is what percent of 150:

35: 150*100 =

(35*100): 150 =

3500: 150 = 23.33

Now we have: 35 is what percent of 150 = 23.33

Question: 35 is what percent of 150?

Percentage solution with steps:

Step 1: We make the assumption that 150 is 100% since it is our output value.

Step 2: We next represent the value we seek with x.

Step 3: From step 1, it follows that 100%=150.

Step 4: In the same vein, x%=35.

Step 5: This gives us a pair of simple equations:

100%=150(1).

x%=35(2).

Step 6: By simply dividing equation 1 by equation 2 and taking note of the fact that both the LHS

(left hand side) of both equations have the same unit (%); we have

\frac{100\%}{x\%}=\frac{150}{35}

Step 7: Taking the inverse (or reciprocal) of both sides yields

\frac{x\%}{100\%}=\frac{35}{150}

Therefore, 35 is 23.33% of 150.

7 0

3 years ago

Divide 405 in the ratio 4:11​

Divide 405 in the ratio 4:11