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Crank
3 years ago
5

Homework: Module 5 Section 2.1 Home

Mathematics
1 answer:
Papessa [141]3 years ago
3 0

Answer:

idk

Step-by-step explanation:

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7 qt. of a 27% saline solution was mixed
mamaluj [8]

Answer:

24% saline

Step-by-step explanation:

Find how much saline is in both solutions:

7(0.27)

= 1.89

3(0.17)

= 0.51

Add this together:

1.89 + 0.51

= 2.4

Since there are 10 quarts in total, the concentration of the mixture can be found by dividing 2.4 by 10:

2.4/10

= 0.24

So, the concentration of the mixture is 24% saline

4 0
3 years ago
HEY BESTIES help me please and thank you 6th grade math
erica [24]

Answer:

Thanks you to

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Eeeek help, I don’t exactly know how to calculate the width of the missing shape!
Anuta_ua [19.1K]

Answer:

Perimeter = 101.2 cm

Step-by-step explanation:

The given figure has a length of 18 cm and width of 24 cm.  A rectangle of length 8.6cm has been cut out, however, the question is asking to find the perimeter, or distance around the figure.  The overall rectangle still has a perimeter of 18 + 18 + 24 + 24 = 84. However, now it also has two additional sides of 8.6cm each, so 8.6 + 8.6 = 17.2.  

Add all the sides together for perimeter:

84 + 17.2 = 101.2 cm

8 0
3 years ago
The graph shows the speed of sally the sloth. How long would it take Sally to travel 9 feet
Ivanshal [37]

Answer:

dude wheres the choices

Step-by-step explanation:

3 0
3 years ago
A standard six-sided die is rolled twice and the top faces are observed. What is the probability that the sum of the numbers on
melisa1 [442]

<u>Answer: </u>

A standard six-sided die is rolled twice and the top faces are observed and the probability that the sum of the numbers on the top faces is 10 is \frac{1}{12}

<u>Solution: </u>

The sample space of two dice outcomes is given as follows:

{(1, 1) (1, 2) (1, 3) (1, 4) (1, 5) (1, 6)

(2, 1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3, 1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4, 1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5, 1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6, 1) (6,2) (6,3) (6,4) (6,5) (6,6) }

Total number of events n(s) = 36

Expected Outcomes = {(4, 6), (5, 5), (6, 4)}

Number of favorable outcomes n(E) = 3

Probability (sum of numbers on the top faces is 10) = \frac{n(E)}{n(s)} = \frac{3}{36} = \frac{1}{12}

Therefore the probability that the sum of the numbers on the top faces is 10 is \frac{1}{12}

3 0
3 years ago
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