Homework: Module 5 Section 2.1 Home

Do this work If one do I will make brainliest her or him please

denpristay [2]

Answer:

If you need the explanation, just ask.

6 0

3 years ago

Whats <br> 3(x+4) In simplyed.

Setler [38]

Answer:

3x + 12

Step-by-step explanation:

Distribute the 3

5 0

3 years ago

Read 2 more answers

John put away 36 of 48 shirts in his closet. Don has 84 shirts. If he put away the same percent, how many shirts did Don put in

Alexeev081 [22]

Answer:

63

Step-by-step explanation:

John's percentage:

36 and 48 have a common factor of 12 so divide both of them by 12.

36/12= 3 and 48/12=4 therefore

so 36/48= 3/4 which is 75% but we don't need to focus on the percent.

Don's no. of shirts:

we know Don has 84 shirts so we say

3/4 of 84= no. of shirts that Don put in his closet

84/4=21 21x3=63

Don put 63 shirts in his closet.

Hope that helped! Anymore questions just ask! :)

3 0

3 years ago

My Notes A large manufacturing plant uses lightbulbs with lifetimes that are normally distributed with a mean of 1600 hours and

Evgen [1.6K]

Answer:

The bulbs should be replaced each 1436.9 hours.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 1600, \sigma = 70$

How often should the bulbs be replaced so that no more than 1% burn out between replacement periods?

This is the first percentile of hours. So it is X when Z has a pvalue of 0.01.

So it is X when Z = -2.33.

$Z = \frac{X - \mu}{\sigma}$

$-2.33 = \frac{X - 1600}{70}$

$X - 1600 = -2.33*70$

$X = 1436.9$

The bulbs should be replaced each 1436.9 hours.

6 0

3 years ago

A prime number less than 100 is selected randomly. what is the probability that its square has units digit $7$?

liberstina [14]

Any number ends with 0, 1, 2, 3, 4, 5, 6, 7, 8 or 9

Given any number. The square of this number is the last digit of square of the original numbers units digit.

For example

23*23 ends with 9 (3*3=9)

149*149 ends with 1 (9*9=81)

2564*2564 ends with 6 (4*4=16)

and so on

so all the possible unit digits of a square number are {0, 1, 4, 5, 6, 9}

because:

0*0= 0 ; 1*1=1; 2*2=4; 3*3=9; 4*4=16; 5*5=25, 6*6=36; 7*7=49; 8*8=64, 9*9=81

Thus, the probability that the square of a number selected from any set of numbers being 7, is 0.

Answer: 0

4 0

3 years ago