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lozanna [386]
2 years ago
15

→

Mathematics
1 answer:
Juli2301 [7.4K]2 years ago
3 0
Answer 5.1
Order them from least to greatest and find the middle number. Or by calculating the mean by adding together the middle values and dividing them by two.
You might be interested in
What is a=16 b= 28 and c=? What would c be?
sergiy2304 [10]
A^2+b^2= c^2
16^2+ 28^2= c^2
 square root of 256+784 = square root of 1,040
32.25=32.25

C= 32.25
3 0
3 years ago
Precal : Note: Triangle may not be drawn to scale. Suppose a = 3 and A = 15 degrees
drek231 [11]

Given:

In a right triangle at B,

\begin{gathered} a=3 \\ A=15^{\circ} \end{gathered}

To find:

The length of the sides b and c and angle B.

Explanation:

Using the trigonometric ratio,

\begin{gathered} sinA=\frac{a}{c} \\ \sin15^{\circ}=\frac{3}{c} \\ c=\frac{3}{\sin15^{\circ}} \\ c=11.59 \\ c\approx11.6 \end{gathered}

Using the trigonometric ratio,

\begin{gathered} \tan A=\frac{a}{b} \\ \tan15^{\circ}=\frac{3}{b} \\ b=\frac{3}{\tan15^{\circ}} \\ b=11.19 \\ b\approx11.2 \end{gathered}

Using the angle sum property,

The angle B becomes,

\begin{gathered} 90+15+B=180 \\ B=180-90-15 \\ B=75^{\circ} \end{gathered}

Final answer:

The values are,

\begin{gathered} b=11.2 \\ c=11.6 \\ B=75^{\circ} \end{gathered}

3 0
1 year ago
Occasionally an airline will lose a bag. Suppose a small airline has found it can reasonably model the number of bags lost each
julia-pushkina [17]

Answer:

a) The probability that the airline will lose no bags next monday is 0.1108

b) The probability that the airline will lose 0,1, or 2 bags next Monday is 0.6227

c) I would recommend taking a Poisson model with mean 4.4 instead of a Poisson model with mean 2.2

Step-by-step explanation:

The probability mass function of X, for which we denote the amount of bags lost next monday is given by this formula

P(X=k) = \frac{e^{-2.2} * {2.2}^k }{k!}

a)

P(X=0) = \frac{e^{-2.2} * {2.2}^0 }{0!} = 0.1108

The probability that the airline will lose no bags next monday is 0.1108.

b) Note that P(X \in \{0,1,2\} = P(X=0) + P(X=1) + P(X=2) . And

P(X=0)+P(X=1)+P(X=2) = e^{-2.2} * (1 + 2.2 + 2.2^2/2) = 0.6227

Therefore, the probability that the airline will lose 0,1, or 2 bags next Monday is 0.6227.

c) If the double of flights are taken, then you at least should expect to loose a similar proportion in bags, because you will have more chances for a bag to be lost. WIth this in mind, we can correctly think that the average amount of bags that will be lost each day will double. Thus, i would double the mean of the Poisson model, in other words, i would take a Poisson model with mean 4.4, instead of 2.2.

6 0
3 years ago
Are the following lines parallel perpendicular or neither y=-5/3x - 5 and y=4/3x - 5​
katrin [286]

Answer:

neither

Step-by-step explanation:

For lines to be parallels the slopes must be equal, for the lines to be perpendicular the lines have to be inverse reciprocals  meaning if you have a slope of 1/2X then the perpendicular line must be -2X

3 0
2 years ago
Walking path across the park is represented by the equation Y equals negative 2X -7. A new path will be built perpendicular to t
Genrish500 [490]

here the equation of path is -2x-7=y

let us find slope of this line by using y=mx+b

so slope m=-2

now new path is perpendicular to this path.

product of slopes of perpendiculars is -1

so slope of new path is 1/2

now it passes through (-2,-3) with slope 1/2

using y=mx+b to get value of b

-3=1/2(-2) +b

b=-2

plugging m=-1/2 and b=-2 in y=mx + b to get the final equation as

y=(-1/2) x -2 is the equation of new path

5 0
3 years ago
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