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3 years ago

Which pair of sneakers has the lowest sale price?

Mathematics

2 answers:

galben [10]3 years ago

8 0

Answer:

15% off $30

Step-by-step explanation:

Naddika [18.5K]3 years ago

3 0

I think air forces their pretty cheap to me it’s like 100$ and they go with any outfit

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What is the equation in point slope form of the line that passes through the point (−1, −3) and has a slope of 4?

Firlakuza [10]

Answer:

(y-(-3))=4(x-(-1))

Step-by-step explanation:

formula for point slope form is:

y-y1=m(x-x1)

just plug in numbers from the point (-1, -3) for x1 and y1. The slope 4, would plug into m.

6 0

4 years ago

A sector of a circle has a central angle of 100 degrees. If the area of the sector is 50pi, what is the radius of the circle

MrMuchimi

The radius of the circle having the area of the sector 50π, and the central angle of the radius as 100° is 6√5 units.

An area of a circle with two radii and an arc is referred to as a sector. The minor sector, which is the smaller section of the circle, and the major sector, which is the bigger component of the circle, are the two sectors that make up a circle.

Area of a Sector of a Circle = (θ/360°) πr², where r is the radius of the circle and θ is the sector angle, in degrees, that the arc at the center subtends.

In the question, we are asked to find the radius of the circle in which a sector has a central angle of 100° and the area of the sector is 50π.

From the given information, the area of the sector = 50π, the central angle, θ = 100°, and the radius r is unknown.

Substituting the known values in the formula Area of a Sector of a Circle = (θ/360°) πr², we get:

50π = (100°/360°) πr²,

or, r² = 50*360°/100° = 180,

or, r = √180 = 6√5.

Thus, the radius of the circle having the area of the sector 50π, and the central angle of the radius as 100° is 6√5 units.

Learn more about the area of a sector at

brainly.com/question/22972014

#SPJ4

8 0

1 year ago

What is an equation of the line that passes through the point (-6,-8) and is parallel to the line x-2y=6?

vfiekz [6]

Answer:

$y=\frac{1}{2}x-5$

Step-by-step explanation:

Hi there!

What we need to know:

Linear equations are typically organized in slope-intercept form: $y=mx+b$ where m is the slope and b is the y-intercept (the value of y when the line crosses the y-axis)
Parallel lines always have the same slope and different y-intercepts

1) Determine the slope (m)

$x-2y=6$

Rearrange this equation into slope-intercept form (this will help us find the slope)

Subtract x from both sides

$x-2y-x=6-x\\-2y=-x+6$

Divide both sides by -2

$y=\frac{1}{2} x-3$

Now, we can identify clearly that the slope of the given line is $\frac{1}{2}$ since it's in the place of m. Because parallel lines always have the same slopes, the line we're currently solving for would therefore have a slope of $\frac{1}{2}$ as well. Plug this into $y=mx+b$ :

$y=\frac{1}{2}x+b$

2) Determine the y-intercept (b)

$y=\frac{1}{2}x+b$

Plug in the given point (-6,-8)

$-8=\frac{1}{2}(-6)+b\\-8=-3+b$

Add 3 to both sides to isolate b

$-8+3=-3+b+3\\-5=b$

Therefore, the y-intercept is -5. Plug this back into $y=\frac{1}{2}x+b$ :

$y=\frac{1}{2}x-5$

I hope this helps!

7 0

3 years ago

Trying to help my daughter can't figure this out.

Anvisha [2.4K]

Answer:

width equals 16

length = 20

Step-by-step explanation:

Hello there!

we know that the perimeter is 72 m

and the width is 4 m less then the length

perimeter is 2w+2l

w=width and l = length

72 + (2x-4) = 72+8 = 80

80 / 4 (because there are 4 values, w, w, l, l ) = 20

so now...

20 - 4 = w

16 = w

and 20 = l

16+16 = 32

20+20 = 40

32+40 = 72

7 0

3 years ago

Solve y'' + 10y' + 25y = 0, y(0) = -2, y'(0) = 11 y(t) = Preview

svetlana [45]

Answer: The required solution is

$y=(-2+t)e^{-5t}.$

Step-by-step explanation: We are given to solve the following differential equation :

$y^{\prime\prime}+10y^\prime+25y=0,~~~~~~~y(0)=-2,~~y^\prime(0)=11~~~~~~~~~~~~~~~~~~~~~~~~(i)$

Let us consider that

$y=e^{mt}$ be an auxiliary solution of equation (i).

Then, we have

$y^prime=me^{mt},~~~~~y^{\prime\prime}=m^2e^{mt}.$

Substituting these values in equation (i), we get

$m^2e^{mt}+10me^{mt}+25e^{mt}=0\\\\\Rightarrow (m^2+10y+25)e^{mt}=0\\\\\Rightarrow m^2+10m+25=0~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{since }e^{mt}\neq0]\\\\\Rightarrow m^2+2\times m\times5+5^2=0\\\\\Rightarrow (m+5)^2=0\\\\\Rightarrow m=-5,-5.$

So, the general solution of the given equation is

$y(t)=(A+Bt)e^{-5t}.$

Differentiating with respect to t, we get

$y^\prime(t)=-5e^{-5t}(A+Bt)+Be^{-5t}.$

According to the given conditions, we have

$y(0)=-2\\\\\Rightarrow A=-2$

and

$y^\prime(0)=11\\\\\Rightarrow -5(A+B\times0)+B=11\\\\\Rightarrow -5A+B=11\\\\\Rightarrow (-5)\times(-2)+B=11\\\\\Rightarrow 10+B=11\\\\\Rightarrow B=11-10\\\\\Rightarrow B=1.$

Thus, the required solution is

$y(t)=(-2+1\times t)e^{-5t}\\\\\Rightarrow y(t)=(-2+t)e^{-5t}.$

6 0

3 years ago