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yaroslaw [1]
3 years ago
14

Juan roller skated for 2 hours 40 minutes with a constant speed of 18 m/h and then for another 1 hour 50 minutes with a constant

speed of 24 m/h. What distance did he go?
Mathematics
1 answer:
Nikolay [14]3 years ago
8 0

Answer: 136 m

Step-by-step explanation:

For first interval,

Time = 2 hours 40 minutes  = 2+\dfrac{40}{60}\text{ hours}\ [\text{1 hour = 60 minutes}]

=2+\dfrac{2}{3}=\dfrac{8}{3}\ \text{hours}

Speed = 18 m/h

Distance = \dfrac{8}{3}\times18=48\ m[Formula : Distance=Speed x time]

For second interval,

Time = 1 hour 50 minutes  = 1+\dfrac{50}{60}\text{ hours}\ [\text{1 hour = 60 minutes}]

=1+\dfrac{5}{6}=\dfrac{11}{3}\ \text{hours}

Speed = 24 m/h

Distance = \dfrac{11}{3}\times24=88\ m

Total distance = 48 m +88 m = 136 m

Hence, he went 136 m.

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4 years ago
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Answer:

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Step-by-step explanation:

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3 years ago
Read 2 more answers
Suppose you earn 3% on a $1,200 deposit for 5 years. Explain how the simple interest is affected if the rate is increased by 1%.
coldgirl [10]
\bf ~~~~~~ \textit{Simple Interest Earned}\\\\
I = Prt\qquad 
\begin{cases}
I=\textit{interest earned}\\
P=\textit{original amount deposited}\to& \$1200\\
r=rate\to 3\%\to \frac{3}{100}\to &0.03\\
t=years\to &5
\end{cases}
\\\\\\
I=1200(0.03)(5)\implies \boxed{I=180}\\\\
-------------------------------

\bf ~~~~~~ \textit{Simple Interest Earned increased by 1\%}\\\\
I = Prt\qquad 
\begin{cases}
I=\textit{interest earned}\\
P=\textit{original amount deposited}\to& \$1200\\
r=rate\to 4\%\to \frac{4}{100}\to &0.04\\
t=years\to &5
\end{cases}
\\\\\\
I=1200(0.04)(5)\implies \boxed{I =240}\\\\
-------------------------------

\bf ~~~~~~ \textit{Simple Interest Earned increased by 1 year}\\\\
I = Prt\qquad 
\begin{cases}
I=\textit{interest earned}\\
P=\textit{original amount deposited}\to& \$1200\\
r=rate\to 3\%\to \frac{3}{100}\to &0.03\\
t=years\to &6
\end{cases}
\\\\\\
I=1200(0.03)(6)\implies \boxed{I =216}
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kipiarov [429]

Answer:

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I hope this helps! :)

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