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Answer:
Niles and Bob were traveling for 6 hours.
Step-by-step explanation:
The speed or rate at which an object is moving can be computed using the formula:
Here:
<em>s</em> = speed
<em>d</em> = distance traveled
<em>t</em> = time taken
It is provided that Niles and Bob sailed at the same time for the same length of time.
Speed of Niles sailboat is, <em>s</em>₁ = 6 mph.
Distance traveled by Niles' sailboat is, <em>d</em>₁ = 36 miles.
Speed of Bob's sailboat is, <em>s</em>₂ = 16 mph.
Distance traveled by Bob's sailboat is, <em>d</em>₂ = 96 miles.
It took both Niles and Bob the same time to travel the respective distance.
Compute the time it took Niles to travel 36 miles at 6 mph speed as follows:
It took Niles 6 hours to travel 36 miles at 6 mph speed.
Compute the time it took Bob to travel 96 miles at 16 mph speed as follows:
It took Bob 6 hours to travel 96 miles at 16 mph speed.
Thus, Niles and Bob were traveling for 6 hours.
Answer:
the linearization is y = 1/4x +5/4
the linearization will produce <em>overestimates</em>
the values computed from this linearization are ...
f(3.98) ≈ 2.245
f(4.05) ≈ 2.2625
Step-by-step explanation:
Apparently, you have ...
from which you have correctly determined that ...
so that f(3) = 2 and f'(3) = 1/4. Putting these values into the point-slope form of the equation of a line, we get the linearization ...
g(x) = (1/4)(x -3) +2
g(x) = (1/4)x +5/4
__
The values from this linearization will be overestimates, as the curve f(x) is concave downward everywhere. The tangent (linearization) is necessarily above the curve everywhere.
__
At the given values, we find ...
g(3.98) = 2.245
g(4.05) = 2.2625
