Answer:
0.1319 or 13.2%
Step-by-step explanation:
You can solve this using the binomial probability formula.
The fact that "obtaining at least two 6s" requires you to include cases where you would get three and four 6s as well.
Then, we can set the equation as follows:
P(X≥x) = ∑(k=x to n) C(n k) p^k q^(n-k)
n=4, x=2, k=2
when x=2 (4 2)(1/6)^2(5/6)^4-2 = 0.1157
when x=3 (4 3)(1/6)^3(5/6)^4-3 = 0.0154
when x=4 (4 4)(1/6)^4(5/6)^4-4 = 0.0008
Add them up, and you should get 0.1319 or 13.2% (rounded to the nearest tenth)
If you need to solve for y
10y-12=4
10y=12+4
10y=16
y=16/10=8/5=1 3/5 or 1.6
Answer:
73.68%
Step-by-step explanation:
To find the amount of increase subtract 33-19 to get 14.
The percent increase is the amount of increase/initial length * 100
So 14/19*100 = 73.684...
Rounding to the nearest hundredth = 73.68%
Round two side of measurement and exercise
