PLs HeLp AsAp<br> Solve the equation:<br> | x + 1 | + |x - 2

What is the area, in square feet, of the isosceles trapezoid below?

marysya [2.9K]

Answer:

A≈78.54

Step-by-step explanation:

A¹=7.7×6.6=50.82(area of rectangle inside)

16.1-7.7=8.4/2=4.2

A²=6.6×4.2=27.72(area of triangles)

A=50.82+27.72=78.54

8 0

2 years ago

in football game the quarterback was tackle behind the line of the scrimmage and lost 7 yards represent the loss of 7 yards as a

umka21 [38]

Seven I hope the answer helped!!

7 0

3 years ago

What is the resistance of a 1.00X10^2 -Ω , a 2.50-kΩ , and a 4.00-k Ω resistor connected in parallel?

Andreas93 [3]

Answer:

Therefore, the total Resistance: R = 93.9 Ω

Step-by-step explanation:

Given

R₁ = 1 × 10²

R₂ = 2.5 kΩ = 2.5 × 10³ Ω

R₃ = 4 kΩ = 4 × 10³ Ω

Given that the given resisters are connected parallel, so using the formula to calculate the total Resistance R:

$\frac{1}{R}\:=\:\frac{1}{R_1}\:+\:\frac{1}{R_2}+\frac{1}{R_3}$

susbtituting R₁ = 1 × 10², R₂ = 2.5 × 10³ Ω, and R₃ = 4 × 10³ Ω

$\frac{1}{R}=\frac{1}{1\times \:10^2}+\frac{1}{2.5\times \:10^3}+\frac{1}{4\times \:10^3}$

Multiply by LCM of R, 100, 2500, and 4000: 20000 R

$\frac{1}{R}\cdot \:20000R=\frac{1}{1\cdot \:10^2}\cdot \:20000R+\frac{1}{2.5\cdot \:10^3}\cdot \:20000R+\frac{1}{4\cdot \:10^3}\cdot \:20000R$

simplify

$20000=213R$

Switch sides

$213R=20000$

Divide both sides by 213

$\frac{213R}{213}=\frac{20000}{213}$

Simplify

$R=\frac{20000}{213}$

$R = 93.9$ Ω

Therefore, the total Resistance: R = 93.9 Ω

4 0

3 years ago

A courier service company wishes to estimate the proportion of people in various states that will use its services. Suppose the

Rasek [7]

Answer:

$\mu_{p} = p = 0.06$

And the standard error is given by:

$SE_{p} = \sqrt{\frac{\hat p(1-\hat p)}{n}}$

And replacing we got:

$SE_[p]= \sqrt{\frac{0.06*(1-0.06)}{373}}= 0.0123$

And we want to find this probability:

$P(\hat p < 0.03)$

We can calculate the z score for this case and we got:

$z = \frac{\hat p -\mu_p}{\Se_p} = \frac{0.03-0.06}{0.0123}= -2.440$

And using the normal distribution table or excel we got:

$P(\hat p < 0.03)= P(Z$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Solution to the problem

For this case we can find the mean and standard error for the sample proportion with these formulas:

$\mu_{p} = p = 0.06$

And the standard error is given by:

$SE_{p} = \sqrt{\frac{\hat p(1-\hat p)}{n}}$

And replacing we got:

$SE_[p]= \sqrt{\frac{0.06*(1-0.06)}{373}}= 0.0123$

And we want to find this probability:

$P(\hat p < 0.03)$

We can calculate the z score for this case and we got:

$z = \frac{\hat p -\mu_p}{\SE_p} = \frac{0.03-0.06}{0.0123}= -2.440$

And using the normal distribution table or excel we got:

$P(\hat p < 0.03)= P(Z$

8 0

4 years ago

during a sale , a shop allows discount of the marked price of clothing . What will a costumer pay for a dress with a marked pric

ollegr [7]

Answer:

35 d

Step-by-step explanation:

3 0

3 years ago

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PLs HeLp AsAp Solve the equation: | x + 1 | + |x - 2 | = 3