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miskamm [114]
2 years ago
14

Which of the following expressions is equivalent to 1/4(8 - 6x + 12)?

Mathematics
2 answers:
valentina_108 [34]2 years ago
7 0
B


TRUST ME MANNNNnnnnnnnnnnnnnnnnnn
lawyer [7]2 years ago
3 0

Answer:

im pretty sure d -3/2x + 5

Step-by-step explanation:

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Help PLEASE (look at picture)
elena-14-01-66 [18.8K]

Answer:

16

Step-by-step explanation:

So for QR is 1-(-3)=4

QT:|-2-2|=4

TS: |-2-(-2)|=4

RS: 2-(-2)=4

and they plus together is 4x

4x4 = 16

I hope this helps, have a blessed day. :D

6 0
1 year ago
Radius=12 round up to the nearest tenth
8090 [49]

Answer:

12.0

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
A school cafeteria sells milk at 25 cents per carton and salads at 45 cents each. one week the total sales for these items were
denis-greek [22]

solution:

Lets start with the most amount that could have been sold.......using guess and check, we can figure out that 290 salads could have been sold, while 8 cartons of milk would have been sold.

The least amount of salads that could have been sold were none.

so,

you have  0<s<290

at least none were sold, and at most 290 were sold

but I do believe you are missing part of the question


4 0
3 years ago
( !!!)<br><br> <br> 4 ÷ 1/2<br><br> ℍ :<br><br> :)
lions [1.4K]

Answer:

8

Step-by-step explanation:

so when you’re dividing fractions alwayes apply keep change flip keep the 4/1 change the division sign to a multiplication sign and flip 1/2 To 2/1 and 4/1 times 2/1 is 8

6 0
2 years ago
Read 2 more answers
Construct a 99% confidthence interval for the population mean .Assume the population has a normal distribution. A group of 19 ra
Kobotan [32]
<h2>Answer with explanation:</h2>

Confidence interval for mean, when population standard deviation is unknown:

\overline{x}\pm t_{\alpha/2}\dfrac{s}{\sqrt{n}}

, where \overline{x} = sample mean

n= sample size

s= sample standard deviation

t_{\alpha/2} = Critical t-value for n-1 degrees of freedom

We assume the population has a normal distribution.

Given, n= 19 , s= 3.8 , \overline{x}=22.4

\alpha=1-0.99=0.01

A) Critical t value for \alpha/2=0.005 and degree of 18 freedom

t_{\alpha/2} = 2.8784

B) Required confidence interval:

22.4\pm ( 2.8744)\dfrac{3.8}{\sqrt{19}}\\\\=22.4\pm2.5058\\\\=(22.4-2.5058,\ 22.4+2.5058)=(19.8942,\ 24.9058)\approx(19.9,\ 24.9)

Lower bound = 19.9 years

Uppen bound = 24.9 years

C) Interpretation: We are 99% confident that the true population mean of lies in (19.9, 24.9) .

5 0
3 years ago
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