Answer:
about 252.78 ft
Step-by-step explanation:
Define angle QMP as α. Then ...
MN = 60·sin(α)
NP = 60·cos(α)
area MPN = (1/2)(MN)(NP) = 1800sin(α)cos(α)
__
PQ = 60tan(α)
area MPQ = (1/2)(MP)(PQ) = 1800tan(α)
__
The ratio of areas is 2.5, so we have ...
1800tan(α) = 2.5·1800sin(α)cos(α)
1 = 2.5cos(α)² . . . . . . divide by 1800tan(α)
cos(α) = √0.4 . . . . . . solve for cos(α)
__
Then the perimeter is ...
Perimeter = MN +NP +PQ +QM = 60sin(α) +60cos(α) +60tan(α) +60/cos(α)
= 60(sin(α) +cos(α) +tan(α) +sec(α))
= 60(0.774597 +0.632456 +1.224745 +1.581139)
= 60(4.212936) = 252.776
The perimeter of the trapezoid is about 252.776 feet.
_____
With perhaps a little more trouble, you can find the exact value to be ...
perimeter = (6√10)(7+√6+√15)
Answer:
The number of unsold cakes was 2
Step-by-step explanation:
<u><em>The question in English is</em></u>
In the school Francisco I. Madero of Ciudad Delicias, the celebration was held for commemorate the arrival of spring, after the parade the stalls were set up of the kermesse. The first grade group bought 8 cakes and sold 3/4 of the total.
How much of the cake was not sold?
Let
x ----> number of cakes sold
y ----> number of cakes that didn't sell
we know that
The first grade group bought 8 cakes
so
-----> equation A
The first grade group sold 3/4 of the total.
so
---> equation B
substitute equation A in equation B
Find the value of y
therefore
The number of unsold cakes was 2
ANSWER:
its $45
Step-by-step explanation:
add it all together...easy
Answer:
4:44 so that you could be there at 5:00 exactly.
Step-by-step explanation:
Answer:
NPV = $13,676.33
Step-by-step explanation:
First, find the present value of the cash inflows. You can solve this question using a Financial calculator;
14,000 per year is a recurring cashflow hence the PMT
PMT = 14,000
I/Y = 10%
N= 9
FV =0
then CPT PV = 80,626.33
NPV = -Initial investment + PV of future cash inflows
NPV = -66,950 + 80,626.33
NPV = $13,676.33
"NPV" button, then , then "CPT".
The answer to the NPV = $13,676.33
