Let the distance of Judy from intersection is x and distance of Jackie from intersection is y.
We convert the given information to equations, step by step.
Point 1: When Jackie is 1 mile farther from the intersection than Judy.
This means y is 1 mile more than x.
So,
y = 1 + x
Point 2: The distance between them is 2 miles more than Judy’s distance from the intersection.
Distance between is x+ y.
So, x+y is 2 miles more than y.
x+y = y + 2
⇒
x = 2
From point 1 we have:
y = 1 + x = 1+ 2 = 3
So,
Distance of Judy from intersection is 2 miles and distance of Jackie from intersection is 3 miles.
So a box of 20 chocolates is divided between a group of people based on age
So the ratio for Sibusiso, Dorris, and Freddy is 2:3:5
Add these together, and you get 10
So to find how much each person gets, divide total amount of chocolates by total age
So (20÷10) = 2
So multiply each age term by 2 and you have your answer
(4:6:10)
So Sibusiso gets 4, Dorris gets 6 and Freddy gets 10
- 5x - 4x + 24 = - 3
9x = 27
x = 3
Let number of fives = x then number of ones = 3x and number of tens = x - 1
so we can create the equation
x + 3x + x-1 + y = 26 where y = number of twenties
so
5x + y = 27
also we have the equation
5x + 3x + 10(x - 1) + 20y = 120
18x + 20y = 130..................................(1)
5x + y = 27 multiply by -20:-
-100x - 20y = -540..............................(2)
Adding equation (1) and (2)
-82x = -410
x = 5, that is 5 fives
Now plug x = 5 into equation 1:-
18(5) + 20y = 130
20y = 40
y = 2 , that is 2 twenties
So the answer is there are (3x) = 15 ones , 5 fives, 4 tens and 2 twenties
