The radius of the circle tangent to sides AC and BC and to the circumcircle of triangle ABC.
r= 24.
<h3>What is the radius of the circle tangent to sides AC and BC and to the circumcircle of triangle ABC.?</h3>
Generally, the equation for side lengths AB is mathematically given as
Triangle ABC has side lengths
Where
- AB = 65,
- BC = 33,
- AC = 56.
Hence
r √ 2 · (89 √ 2/2 − r √ 2) = r(89 − 2r),
r = 89 − 65
r= 24.
In conclusion, The radius of the circle tangent to sides AC and BC and to the circumcircle of triangle ABC.
r= 24.
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Answer:
C
Step-by-step explanation:
6x^2-x-2 this is of the form ax^2+bx+c
jk=ac=-12 and j+k=b=-1 so j and k must be -4 and 3 so
6x^2+3x-4x-2
3x(2x+1)-2(2x+1)
(3x-2)(2x+1)
Answer:
YES YOU ARE RIGHT!!! JUST SEE WHAT EQUALS TO =? THIS IS LIKE EQUATIONS BUT WITH FRACTIONS AND THE CALCULATOR WILL HELP ALOT I PROMISEEE:)
Step-by-step explanation:
