Answer:
Her usual speed is 5 miles an hour.
Step-by-step explanation:
Since it takes one hour for her to run ten miles that means she is running at 10 miles an hour. So if you divide that by 2 it would be five.
<h2><em><u>
Have a nice and great day.</u></em></h2>
Answer:
<h2>

</h2>
Step-by-step explanation:
<em><u>Given</u></em><em><u> </u></em><em><u> </u></em>

<em><u>Since</u></em><em><u>,</u></em>

<em><u>Hence</u></em><em><u>,</u></em>


Answer:
The answer is B
Step-by-step explanation:
I hope this has helped you! Have a Good Day!!! :)
Ignoring the "?" in your question:

If the "?" is a squared symbol that wasn't caught:

Use the quadratic formula

to get the solutions:

as you can see, the discriminant is negative, so the equation has no solution.