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AveGali [126]
3 years ago
5

Been up all night on this problem is around 2:25 am. Please help me!

Mathematics
2 answers:
lord [1]3 years ago
8 0

Answer:

#1 100%

not sure about #2

Step-by-step explanation:

algol133 years ago
6 0
The answer is e I think
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Help with this one please do
vaieri [72.5K]

Question 1 - 37 students took the test

Question 2 - 16 students scored between 20 and 40 points

- Ari -

5 0
3 years ago
Question:
Genrish500 [490]

Answer:

x=56 and the exterior angle is 116

Step-by-step explanation:

We will call the unknown angle in the triangle y.  Angle y and the angle (2x +4) form a straight line so they make 180 degrees.

y + 2x+4 =180

Solve for y by subtracting 2x+4 from each side.

y + 2x+4 - (2x+4) =180 - (2x+4)

y = 180-2x-4

y = 176-2x


The three angles of a triangle add to 180 degrees

x+ y+ 60 = 180

x+ (176-2x)+60 = 180

Combine like terms

-x +236=180

Subtract 236 from each side

-x+236-236 = 180-236

-x = -56

Multiply each side by -1

-1*-x = -56*-1

x=56

The exterior angle is 2x+4.  Substitute x=56 into the equation.

2(56)+4

112+4

116


8 0
4 years ago
Which expression is equivalent to (f + g)(4)?​
krok68 [10]

Answer:

4f+4g

Step-by-step explanation:

6 0
3 years ago
Two experiments are defined below. An event is defined for each of the experiments.
attashe74 [19]
The answer should most likely be A. I think
5 0
3 years ago
2. CTfastrak bus waiting times are uniformly distributed from zero to 20 minutes. Find the probability that a randomly selected
Juliette [100K]

Answer:

b. 0.25

c. 0.05

d. 0.05

e. 0.25

Step-by-step explanation:

if the waiting time x follows a uniformly distribution from zero to 20, the probability that a passenger waits exactly x minutes P(x) can be calculated as:

P(x)=\frac{1}{b-a}=\frac{1}{20-0} =0.05

Where a and b are the limits of the distribution and x is a value between a and b. Additionally the probability that a passenger waits x minutes or less P(X<x) is equal to:

P(X

Then, the probability that a randomly selected passenger will wait:

b. Between 5 and 10 minutes.

P(5

c. Exactly 7.5922 minutes

P(7.5922)=0.05

d. Exactly 5 minutes

P(5)=0.05

e. Between 15 and 25 minutes, taking into account that 25 is bigger than 20, the probability that a passenger will wait between 15 and 25 minutes is equal to the probability that a passenger will wait between 15 and 20 minutes. So:

P(15

6 0
3 years ago
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