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3 years ago

Plzz help!!!! Which set of ordered pairs corresponds to the graph?

Mathematics

2 answers:

adelina 88 [10]3 years ago

5 0

Answer:

Option 3rd is correct

Step-by-step explanation:

(1,-6),(2,-4),(2,-2),(4,-2),(6,0)

oee [108]3 years ago

3 0

The third option is correct

A(1,-6)
B(2,-4)
C(2,-2)

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Given that log 2 = 0.3010 and log 3 = 0.4771 , how can we find log 6 ?

bearhunter [10]

Answer:

$\sf \log_{10}6=0.7781$

Step-by-step explanation:

<u>Given</u>:

$\sf \log_{10} 2 = 0.3010$

$\sf \log_{10} 3 = 0.4771$

To find log₁₀ 6, first rewrite 6 as 3 · 2:

$\sf \implies \log_{10}6=\log_{10}(3 \cdot 2)$

$\textsf{Apply the log product law}: \quad \log_axy=\log_ax + \log_ay$

$\implies \sf \log_{10}(3 \cdot 2)=\log_{10}3+\log_{10}2$

Substituting the given values for log₁₀ 3 and log₁₀ 2:

$\begin{aligned} \sf \implies \log_{10}3+\log_{10}2 & = \sf 0.4771+0.3010\\ & = \sf 0.7781 \end{aligned}$

Therefore:

$\sf \log_{10}6=0.7781$

Learn more about logarithm laws here:

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5 0

1 year ago

Read 2 more answers

In 1982 Abby’s mother scored at the 93rd percentile in the math SAT exam. In 1982 the mean score was 503 and the variance of the

oksian1 [2.3K]

Answer:

The percentle for Abby's score was the 89.62nd percentile.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation(which is the square root of the variance) $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Abby's mom score:

93rd percentile in the math SAT exam. In 1982 the mean score was 503 and the variance of the scores was 9604.

93rd percentile. X when Z has a pvalue of 0.93. So X when Z = 1.476.

$\mu = 503, \sigma = \sqrt{9604} = 98$