Question

Given that log 2 = 0.3010 and log 3 = 0.4771 , how can we find log 6 ? ​

Answer 1

Step-by-step explanation:

log 6 = log (2×3) = log 2 + log 3 = 0.3010+0.4771

=0.7781

Answer 2

Answer:

$\sf \log_{10}6=0.7781$

Step-by-step explanation:

Given:

$\sf \log_{10} 2 = 0.3010$

$\sf \log_{10} 3 = 0.4771$

To find log₁₀ 6, first rewrite 6 as 3 · 2:

$\sf \implies \log_{10}6=\log_{10}(3 \cdot 2)$

$\textsf{Apply the log product law}: \quad \log_axy=\log_ax + \log_ay$

$\implies \sf \log_{10}(3 \cdot 2)=\log_{10}3+\log_{10}2$

Substituting the given values for log₁₀ 3 and log₁₀ 2:

$\begin{aligned} \sf \implies \log_{10}3+\log_{10}2 & = \sf 0.4771+0.3010\\ & = \sf 0.7781 \end{aligned}$

Therefore:

$\sf \log_{10}6=0.7781$

Learn more about logarithm laws here:

brainly.com/question/27953288

brainly.com/question/27963321