You get the hypothenuse by doing √a²+b² = c
So....
Square both terms
x² + (3x+3)² = 625
x² + 9x² + 18x + 9 - 625 = 0
10x² + 18x - 616 = 0
x₁,₂ = (-b±√Δ)/2a
Δ = b²-4ac
You call a 10, b 18 and c -616
x1,2 = (-18±√18²-4*10*-616)/2*10
x1,2 = (-18±√324+24640)/20
x1,2 = (-18±√24964)/20
x1,2 = (-18<span>±158)/20
x1 = -18+158/20 = 140/20 = 7
x2 = (-18-158)/20 = -176/20 = -44/5
Pick the first solution
So one leg is 7 and the other is 3(7+1) = 3(8) = 24
Let's verify </span>√24²+7² = √576+49 = √625 = 25
Answer:
Domain: x0 or [0,infinity)
Step-by-step explanation:
f(x)= and g(x)=3-x
We are told to multiply the two functions so we multiply:
(fg)(x)=*(3-x)
(fg)(x)=3-x
Now this is a square root function and it can only go to the right because the square roots of numbers less than 0 are imaginary numbers. Therefore the domain must be greater than or equal to 0.
Distribute -3.2 through the parentheses
Cancel equal terms on both sides of the equation
Add the decimals
<em>Thus, The expression are equivalent at b = 9.12...~</em>
I think the best answer would probably be 1
Your answer would be 105. Hope this helps!