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marysya [2.9K]
3 years ago
15

The percent frequency distributions of job satisfaction scores for a sample of information systems (IS) senior executives and mi

ddle managers are as follows. The scores range from a low of 1 (very dissatisfied) to a high of 5 (very satisfied).
Job SatisfactionScore - IS SeniorExecutives (%) - IS MiddleManagers (%)
1 - 5 - 2004
2 - 9 - 10
3 - 3 - 12
4 - 42 - 46
5 - 41 - 28
(a) Develop a probability distribution for the job satisfaction score of a randomly selected senior executive. xf(x) 1 2 3 4 5
(b) Develop a probability distribution for the job satisfaction score of a randomly selected middle manager. xf(x) 1 2 3 4 5
(c) What is the probability that a randomly selected senior executive will report a job satisfaction score of 4 or 5?
Mathematics
1 answer:
stich3 [128]3 years ago
8 0

Answer:

a. Probability distribution is given below

Scores Ex, x. 1 2 3 4 5

P(X=x). 0.05 0.09 0.03 0.42 0.41

b. Scores mg, Y 1. 2. 3. 4. 5

P(Y=y). 0.04. 0.1. 0.12 0.46 .28

c. probability that a randomly selected senior executive will report a job satisfaction score of 4 or 5.

P(4 or 5) =p(x=4) +p(x=5)

= 0.42 + 0.41=0.83

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To find this, you can simply multiple both the numerator and denominator (top and bottom) by any number as long as it's the same number for both top and bottom.
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Step-by-step explanation:

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Show work please for number 2
Pavlova-9 [17]

The combined distance between CD and DE is CE, so...

2x+4 + 6 = x+14   Simplify like terms..

2x + 10 = x + 14      Subtract x from both sides..

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<h2><u><em>x = 4</em></u></h2>

Proof: 2 (4) + 4 + 6 = 4 + 14

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    <em> Check</em>

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