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trasher [3.6K]
2 years ago
7

Solve system of equations y=3/4x+2 5x+4y=-24

Mathematics
1 answer:
satela [25.4K]2 years ago
6 0

Answer:

\left \{ {{y=-1} \atop {x=-4}} \right.

Step-by-step explanation:

\left \{ {{y=\frac{3}{4} x+2} \atop {5x+4y=-24}} \right.  \left \{ {{y=\frac{3}{4}x+2 } \atop {5x+4*(\frac{3}{4}x+2)=-24 }} \right. \left \{ {{y=\frac{3}{4}x+2 } \atop {5x+3x+8=-24}} \right.  \left \{ {{y=\frac{3}{4}x+2 } \atop {8x=-32}} \right. \\\left \{ {{y=\frac{3}{4}x+2 } \atop {x=-4}} \right.  \left \{ {{y=\frac{3}{4}*(-4)+2 } \atop {x=-4}} \right.  \left \{ {{y=-3+2} \atop {x=-4}} \right. =>\left \{ {{y=-1} \atop {x=-4}} \right.

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Step-by-step explanation:

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3 years ago
For the given values of n and d, find integers q and r such that n = dq + r and 0 ≤ r &lt; d. n = −67, d = 8
Firlakuza [10]

Answer:

q = 8

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Step-by-step explanation:

Given

n = dq + r

0 \le r < d

n = 67 --- not -67

d = 8

Required

Find q and r

Substitute values for d and b

n = dq + r

67 = 8 * q + r

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Make q the subject

q = \frac{67 - r}{8}

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3 years ago
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