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3 years ago

5

What is ( 7v + 5 ) – ( 2v + 2 )

1 answer:

lara [203]3 years ago

5 0

Answer:

5v+3. I hope I helped :'D

<u>Steps for answer!</u>

1. Remove parentheses.

7v+5-2v-2

2. Collect like terms.

(7v-2v)+(5-2)

3. Simplify.

5v+3

<u></u>

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Solve 2cos ²y -siny -1=0 for 0° ≤y≤360°

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$\displaystyle\bf\\\boxed{\bf sin\,y=x}\\\\2x^2+x-1=0\\\\x_{12}=\frac{-b\pm\sqrt{b^2-4ac}}{2a}=\frac{-1\pm\sqrt{1-4\cdot2\cdot(-1)}}{2\cdot2}=\\\\=\frac{-1\pm\sqrt{1+8}}{4}=\frac{-1\pm\sqrt{9}}{4}=\frac{-1\pm3}{4}\\\\x_1=\frac{-1+3}{4}=\frac{2}{4}=\boxed{\bf\frac{1}{2}}\\\\x_2=\frac{-1-3}{4}=\frac{-4}{4}=\boxed{\bf-1}\\\\sin\,y=\frac{1}{2}\\\\\boxed{\bf y_1=\frac{\pi}{6}~~or~~(30^o)}\\\\\boxed{\bf y_2=\frac{5\pi}{6}~~or~~(150^o)}\\\\sin\,y=-1\\\\\boxed{\bf y_3=\frac{3\pi}{2}~~or~~(270^o)}$

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3 years ago

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3 years ago

Convert 31 minutes to seconds

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Step-by-step explanation: 1,860 Seconds Is Equal To 31 Minutes Hope It Helped

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4 years ago

Dilate a triangle with vertices (0,0), (0,2) and (2,0) using the scale factor k=3. What is the value of the ratio (new to origin

seropon [69]

Answer:

Part a) The ratio of the perimeters is $3$

Part b) The ratio of the areas is $9$

Step-by-step explanation:

Part A) What is the value of the ratio (new to original) of the perimeters?

we know that

If two figures are similar, then the ratio of its perimeters is equal to the scale factor

Let

z-----> the scale factor

x-----> the perimeter of the new triangle

y-----> the perimeter of the original triangle

$z=\frac{x}{y}$

we have

$z=3$

substitute

$\frac{x}{y}=3$

Part B) What is the value of the ratio (new to original) of the areas?

we know that

If two figures are similar, then the ratio of its areas is equal to the scale factor squared

Let

z-----> the scale factor

x-----> the area of the new triangle

y-----> the area of the original triangle

$z^{2}=\frac{x}{y}$

we have

$z=3$

substitute

$\frac{x}{y}=3^{2}$

$\frac{x}{y}=9}$

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3 years ago

Please answer someone

Korolek [52]

Answer:

answer C

Step-by-step explanation:

hello

set A is $10^x$

set B is 1000+50(x-1)

so set A is an exponential function and the values increase at a faster rate than set B

hope this helps

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