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3 years ago

If Plz help ASAP! Thank you

Mathematics

1 answer:

Licemer1 [7]3 years ago

6 0

Answer:

Step-by-step explanation:

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Read 2 more answers

Find the slope of the line passing through the points of (3,-5) and (-9,-6)

slavikrds [6]

Answer:

m = ---

Step-by-step explanation:

The formula is y2-y1

---------

x2-x1

(x1,y1) (x2,y2)

(3,-5) (-9,-6)

You get the 2 Y's and subtract them

Do the same with the X's

Y's above , X's below

(y2- y1)

⬇

-6-(-5) -1 1

--------- = ---- = ---- = m

-9-(3) -12 12

⬆

(×2- x1)

This equation is backwards, thats why it was harder to understand. (-9,-6) is farther left and below point (3,-5), making it the REAL first point in the equation.

5 0

3 years ago

..................................

yanalaym [24]

Answer:

The answer is a² .

Step-by-step explanation:

You have to substitute x and y into the expression :

$let \: x = a \cos(θ) \\ let \: y = a \sin( θ)$

${x}^{2} + {y}^{2} = {(a \cosθ )}^{2} + {(a \sinθ) }^{2}$

${x}^{2} + {y}^{2} = {a}^{2}( {cos}^{2}θ) + {a}^{2} ({sin}^{2}θ)$

Next, you have to apply Basic Trigonometric Identity :

${sin}^{2} θ + {cos}^{2} θ = 1$

${x}^{2} + {y}^{2} = {a}^{2} ( {cos}^{2} θ + {sin}^{2} θ)$

${x}^{2} + {y}^{2} = {a}^{2} (1)$

${x}^{2} + {y}^{2} = { a}^{2}$

8 0

3 years ago