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kupik [55]
3 years ago
9

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Mathematics
1 answer:
algol [13]3 years ago
4 0

Answer:

What do you want to know

Step-by-step explanation:

Please tell me so I can help you!! :)

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In ΔUVW, w = 9 cm, v = 2.2 cm and ∠V=136°. Find all possible values of ∠W, to the nearest 10th of a degree.
Alja [10]

Complete Question

In ΔUVW, w = 9 cm, v = 22 cm and ∠V=136°. Find all possible values of ∠W, to the nearest 10th of a degree.

Answer:

16.5°

Step-by-step explanation:

In ΔUVW, w = 9 cm, v = 22 cm and ∠V=136°. Find all possible values of ∠W, to the nearest 10th of a degree.

We solve using Sine rule formula

a/sin A = b/sin B

We are solving for angle W

∠V=136°

Hence:

22 /sin 136 = 9 /sin W

Cross Multiply

22 × sin W = sin 136 × 9

sin W = sin 136 × 9/22

W = arc sin [sin 136 × 9/2.2]

W = 16.50975°

W = 16.5°

3 0
3 years ago
Please help picture included!!
Triss [41]
I think the answer is C
8 0
4 years ago
Baka Baka Banana<br><br> Who says this in One Piece?
aleksklad [387]

Answer:

Lol don’t know

Step-by-step explanation:

Have a nice day uvu

4 0
3 years ago
Read 2 more answers
On the first play during the football game our team gained 5 yards. Between both the second and third play our team lost eight y
Maurinko [17]

Answer:

loss

Step-by-step explanation:

you might want to check someone else answer first tho

7 0
3 years ago
Plutonium–238 has a yearly decay constant of 7.9 × 10-3. If an original sample has a mass of 15 grams, how long will it take to
eduard
The answer is 28 years

At = A0 * e^(-k * t)
At = 12 g
A0 = 15 g
k = 7.9 × 10^-3 = 0.0079 
t = ?

12 = 15 * e^(-0.0079 * t)
12/15 = e^(-0.0079 * t)
0.8 = e^(-0.0079 * t)

Logarithm both sides (because ln(e) = 1:
ln(0.8) = ln(e^(-0.0079 * t))
ln(0.8) = (-0.0079 * t) * ln(e)
-0.223 = -0.0079 * t
t = -0.223 / -0.0079
t = 28.23
t ≈ 28 years
8 0
3 years ago
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