Step-by-step explanation:
g(x) = 3x - 2
g(-4) = 3(-4) - 2
= -12 -2
= -14
Answer:
0,-11
Step-by-step explanation:
-p^2 − 11p = 0
Factor out -p
-p( p+11) =0
Using the zero product property
-p =0 p+11 =0
p =0 p = -11
Answer:
The numerator factors to
The denomenator factors to
9514 1404 393
Answer:
17. 5
18. 17
Step-by-step explanation:
The distance formula is used for the purpose.
d = √((x2 -x1)² +(y2 -y1)²)
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17. d = √((3-6)² +(1-5)²) = √((-3)² +(-4)²) = √(9+16) = √25 = 5
The distance between the points is 5 units.
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18. d = √((-1-7)² +(12-(-3))²) = √(64 +225) = √289 = 17
The distance between the points is 17 units.
A <span>counterclockwise rotation of 270º about the origin is equivalent to a </span><span>clockwise rotation of 90º about the origin.
Given a point (4, 5), the x-value, i.e. 4 and the y-value, i.e. 5 are positive, hence the point is in the 1st quadrant of the xy-plane.
A clockwise rotation of </span><span>90º about the origin of a point in the first quadrant of the xy-plane will have its image in the fourth quadrant of the xy-plane. Thus the x-value of the image remains positive but the y-value of the image changes to negative.
Also the x-value and the y-value of the original figure is interchanged.
For example, given a point (a, b) in the first quadrant of the xy-plane, </span><span>a counterclockwise rotation of 270º about the origin which is equivalent to a <span>clockwise rotation of 90º about the origin will result in an image with the coordinate of (b, -a)</span>
Therefore, a </span><span>counterclockwise rotation of 270º about the origin </span><span>of the point (4, 5) will result in an image with the coordinate of (5, -4)</span> (option C)
