Given data:
Total number of socks: 25
10 white socks
8 black socks
7 brown socks
Probability select a black sock:
![\begin{gathered} P(B)=\frac{\#\text{black socks}}{\#total\text{ of socks}} \\ \\ P(B)=\frac{8}{25}=0.32 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20P%28B%29%3D%5Cfrac%7B%5C%23%5Ctext%7Bblack%20socks%7D%7D%7B%5C%23total%5Ctext%7B%20of%20socks%7D%7D%20%5C%5C%20%20%5C%5C%20P%28B%29%3D%5Cfrac%7B8%7D%7B25%7D%3D0.32%20%5Cend%7Bgathered%7D)
Then, the probability that if you randomly select a sock from the drawer that it will still be black is 0.32
Answer:
The value of b = 1/36
As exponent decreases, each previous value is divided by 6
If the table was extended, the value of 6^-3 would be 1/216
Step-by-step explanation:
Given in the question a table containing power of 6
We will use negative rule of exponent to write the equivalent of negative power of 6
b^{-n}= 1 / b^{n}
we know that
![6^{1} = 6](https://tex.z-dn.net/?f=6%5E%7B1%7D%20%3D%206)
so
![6^{-1} = \frac{1}{6^{1} }](https://tex.z-dn.net/?f=6%5E%7B-1%7D%20%3D%20%5Cfrac%7B1%7D%7B6%5E%7B1%7D%20%7D)
= 1/6
and
![6^{2} = 36\\](https://tex.z-dn.net/?f=6%5E%7B2%7D%20%3D%2036%5C%5C)
So,
![6^{-2} = \frac{1}{6^{2} }](https://tex.z-dn.net/?f=6%5E%7B-2%7D%20%3D%20%5Cfrac%7B1%7D%7B6%5E%7B2%7D%20%7D)
= ![\frac{1}{36}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B36%7D)
Answer: Isosceles Triangle (if that was what you were looking for)
Step-by-step explanation:
Answer:
it's a en enginuityy gotta have them exstraw letters