In order to understand if the inequalities are always, never or sometimes true, you need to perform the calculations:
A) <span>9(x+2) > 9(x-3)
9x + 18 > 9x - 27
the two 9x cancel out and you get:
+18 > -27
which is always true.
B) <span>6x-13 < 6(x-2)
6x - 13 < 6x - 12</span>
</span><span>the two 6x cancel out and you get:
- 13 < -12
which is always true
C) </span><span>-6(2x-10) + 12x ≤ 180
-12x +60 +12x </span>≤ 180
-12x and +<span>12x cancel out and you get:
60 </span><span>≤ 180
which is always true.
All three cases are always true.</span>
Answer:
cost of nachos = $3.45
Cost of tacos = $1.5
Step-by-step explanation:
Let
x = cost of nachos
y = cost of tacos
11x + 18y = 64.95 (1)
6x + 15y = 43.20 (2)
Multiply (1) by 6 and (2) by 11 to eliminate x
66x + 108y = 389.70
66x + 165y = 475.20
Subtract to eliminate x
165y - 108y = 475.20 - 389.70
57y = 85.50
y = 85.50/57
y = 1.5
Substitute y = 1.5 to find x
11x + 18y = 64.95 (1)
11x + 18(1.5) = 64.95
11x + 27 = 64.95
11x = 64.95 - 27
11x = 37.95
x = 37.95/11
x = 3.45
cost of nachos = $3.45
Cost of tacos = $1.5
Ce clasă ești sa văd daca te pot ajuta
Given:
In a right triangle at B,
To find:
The length of the sides b and c and angle B.
Explanation:
Using the trigonometric ratio,
Using the trigonometric ratio,
Using the angle sum property,
The angle B becomes,
Final answer:
The values are,
2x-7y=18 _(1)
-2x+4y=5
11y=23 , Y=23/11 sub in 1
2x-7×23/11=18
2x = 18×11 + 7×23
x = ( 198 + 161 )/2 = 359/2
