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Darina [25.2K]
3 years ago
9

HELP PLEASE! WILL MARK U BRAIN-LIST

Mathematics
2 answers:
Semmy [17]3 years ago
7 0

Answer:

D. 10.20 cm

Step-by-step explanation:

faust18 [17]3 years ago
7 0
Choice D)10.20cm i hope that helps
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The first 25 prime numbers (all the prime numbers less than 100) are: 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97.

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Suppose we have collected times, in minutes, that it takes volunteers to complete a set of pencil and paper mazes. Volunteers ar
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Is an experimental study

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In an observational study you don't control any aspect of the investigation you just observe the variables that you determined since the beginning without any intervention.

In this case you are controlling who sees one or the other video, then you are controlling one of the variables that is the type of video each group sees and because of this it is an experimental study. Researchers designed an experiment to prove the null hypothesis they had.

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3 years ago
What is the answer to 5 x 2 x 2 + 2?
Sedbober [7]
It is 22 cuz 5 * 2 is 10 and 10 * 2 IS 20 + 2=22

7 0
4 years ago
Read 2 more answers
8(7 + 23) = 8(7) + 8(?)
34kurt
Answer: 23

When using multiplication with brackets, you multiply the number by all the numbers within the bracket before adding them together.

Therefore when it is 8(7 + 23) it basically means: 8(7) + 8(23)
7 0
3 years ago
Read 2 more answers
A worker was paid a salary of $10,500 in 1985. Each year, a salary increase of 6% of the previous year's salary was awarded. How
Mazyrski [523]
Note that 6% converted to a decimal number is 6/100=0.06. Also note that 6% of a certain quantity x is 0.06x.

Here is how much the worker earned each year:


In the year 1985 the worker earned <span>$10,500. 

</span>In the year 1986 the worker earned $10,500 + 0.06($10,500). Factorizing $10,500, we can write this sum as:

                                            $10,500(1+0.06).



In the year 1987 the worker earned

$10,500(1+0.06) + 0.06[$10,500(1+0.06)].

Now we can factorize $10,500(1+0.06) and write the earnings as:

$10,500(1+0.06) [1+0.06]=$10,500(1.06)^2.


Similarly we can check that in the year 1987 the worker earned $10,500(1.06)^3, which makes the pattern clear. 


We can count that from the year 1985 to 1987 we had 2+1 salaries, so from 1985 to 2010 there are 2010-1985+1=26 salaries. This means that the total paid salaries are:

10,500+10,500(1.06)^1+10,500(1.06)^2+10,500(1.06)^3...10,500(1.06)^{26}.

Factorizing, we have

=10,500[1+1.06+(1.06)^2+(1.06)^3+...+(1.06)^{26}]=10,500\cdot[1+1.06+(1.06)^2+(1.06)^3+...+(1.06)^{26}]

We recognize the sum as the geometric sum with first term 1 and common ratio 1.06, applying the formula

\sum_{i=1}^{n} a_i= a(\frac{1-r^n}{1-r}) (where a is the first term and r is the common ratio) we have:

\sum_{i=1}^{26} a_i= 1(\frac{1-(1.06)^{26}}{1-1.06})= \frac{1-4.55}{-0.06}= 59.17.



Finally, multiplying 10,500 by 59.17 we have 621.285 ($).


The answer we found is very close to D. The difference can be explained by the accuracy of the values used in calculation, most important, in calculating (1.06)^{26}.


Answer: D



4 0
3 years ago
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