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3 years ago

Square root of 16 over 121

1 answer:

3 0

$\sqrt{ \frac{16}{121} } = \sqrt{( \frac{4}{11})^{2} } =| \frac{4}{11}|= \frac{4}{11}$

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a can of soup has a volume of 20 pi cubic inches. the diameter of the can is 4 inches. What is the height of the can

ozzi

Answer:

<h3>5 inches</h3>

Step-by-step explanation:

A can is cylindrical in nature and volume of a cylinder is expressed as;

V = πr²h where;

r is the radius of the cylindrical can

h is the height of the can.

Given parameters

Volume of the can of soup = 20πin³

diameter of the can = 4inches

Since diameter = 2r

radius = d/2 = 4/2 = 2inches

Required parameter.

Height of the can

Substituting the given parameters into the formula to get the height h will give;

20π = πr²h

20 = r²h

20 = 2²h

20 = 4h

Divide both sides by 4:

4h/4 = 20/4

h = 5inches

<em>Hence the heighr of the can is 5 inches</em>

4 0

3 years ago

Write an equation of the line that passes through (2,7) and is parallel to the line shown ( please help !! )

Anna007 [38]

Answer:

$y=2x+3$

Step-by-step explanation:

We will first need to determine the slope of the line shown.

We know that it passes through the two points (-2, -2) and (1, 4).

Thus, we can use the slope formula to find the slope between the two points:

$\displaystyle m=\frac{y_2-y_1}{x_2-x_1}$

Let (-2, -2) be (x₁, y₁) and let (1, 4) be (x₂, y₂). Substitute:

$\displaystyle m=\frac{4-(-2)}{1-(-2)}=\frac{6}{3}=2$

Hence, the slope of the original line was 2.

Since we want the new line to be parallel, the slope of the new line must also be 2.

We know that the slope is 2 and it passes through the point (2, 7).

So, we can use the point-slope form:

$y-y_1=m(x-x_1)$

We will substitute 2 for m. We will also let (2, 7) be (x₁, y₁). Substitute:

$y-7=2(x-2)$

Solve for y. Distribute the right:

$y-7=2x-4$

Add 7 to both sides. Hence, our equation is:

$y=2x+3$

6 0

3 years ago

Solve for b.<br> r = (b-5)m

alukav5142 [94]

Answer:

b=5m+r/m

Step-by-step explanation:

Let's solve for b.

r=(b−5)(m)

Step 1: Flip the equation.

bm−5m=r

Step 2: Add 5m to both sides.

bm−5m+5m=r+5m

bm=5m+r

Step 3: Divide both sides by m.

bm/m=5m+r/m

b=5m+r/m

Answer:

b=5m+r/m

6 0

3 years ago

Read 2 more answers

This is a pre calculus question that I need help with, serious answer PLEASE and thank you! Will give brainliest.

IRISSAK [1]

The wording of this question is a bit confusing... You can't write a sequence in sigma notation, but rather a series or sum. I think the question is asking you to write the sum of the sequence,

$\dfrac12,\dfrac14,\dfrac18,\ldots,\dfrac1{64}$

which would be

$\dfrac12+\dfrac14+\dfrac18+\cdots+\dfrac1{64}$

in sigma notation.

To do this, notice that the denominator in each term is a power of 2, starting with $2^1=2$ and ending with $2^6=64$ . So in sigma notation, this series is