Assuming that the 120 faces have all numbers from 1 to 120 printed on them, we have a dice that can output all numbers between 1 and 120 with the same probability of 1/120.

So, the expected value is

$\displaystyle \sum_{i=1}^{120}i\cdot p(i) = \sum_{i=1}^{120}i\cdot \dfrac{1}{120}=\dfrac{1}{120}\sum_{i=1}^{120}i=\dfrac{1}{120}\dfrac{120\cdot 121}{2}=\dfrac{121}{2}=60.5$

5 0

3 years ago

a conical tent of the given volume has to be constructed find the ratio of the height to the radius of the base so as to minimiz

kupik [55]

<span>A conical tent of the given capacity (volume) has to be constructed.</span>

5 0

4 years ago

How to write 3/8 as a percent

Leni [432]

The answer is 37.5% hope this helps

5 0

3 years ago

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