Answer:
y-1=5(x-3)
Step-by-step explanation:
y=mx+b where m=slope and b=y-intercept,
y-y1=m(x-x1)
y-1=5(x-3)
The complete question is
Which statement is true about the factorization of 30x² + 40xy + 51y²<span>?
A. The factorization of the polynomial is 10(3x2 + 4xy + 5y2).
B. The polynomial can be rewritten as the product of a trinomial and xy.
C. The greatest common factor of the polynomial is 51x2y2.
D. The polynomial is prime, and the greatest common factor of the terms is 1.
we know that
case A) </span>is not right because 10 is not a common factor of the three terms.
case B) is not right because the original polynomial is already a trinomial
case C) is not right because the terms do not contain 51x^2y^2
<span>case D) is right
because
</span><span>Factors of 30 are-----> 1,2,3,5,6,10,15,30
</span>Factors of 40 are-----> 1,2,4,5,8,10,20,40
Factors of 51 are-----> 1,51
<span>so
</span><span>The "Greatest Common Factor" is the largest of the common factors
</span><span>the GFC is 1
therefore
the answer is the option
</span>D. The polynomial is prime, and the greatest common factor of the terms is 1<span>
</span>
Answer:
When a shape is transformed by rigid transformation, the sides lengths and angles remain unchanged.
Rigid transformation justifies the SAS congruence theorem by keeping the side lengths and angle, after transformation.
Assume two sides of a triangle are:
And the angle between the two sides is:
When the triangle is transformed by a rigid transformation (such as translation, rotation or reflection), the corresponding side lengths and angle would be:
Notice that the sides and angles do not change.
Hence, rigid transformation justifies the SAS congruence theorem by keeping the side lengths and angle, after transformation.
Step-by-step explanation:
Answer:
Chuck's speed is 37 mi/h
.
Step-by-step explanation:
We're asked to find the speed, Chuck, with some given information.
To do this, let's first recognize the simplified velocity equation:
speed = distance/time
or, rearranging to solve for time:
time = distance/speed
let's write this using symbols to simplify things:
time = s/v
s= distance
v= velocity
we're given that
1. s
Chuck
=
185 mi
2. sDana= 160 mi
3. vDana= x
4. vChuck= x+5
Let's plug these values in for two separate equations for each person:
Chick: t = 185/x+5
Dana: t = 160 mi/x
We're asked to find Chuck's speed given that the time intervals are equal, so what we can do is set these two equations (which are solved for the time,t
), equal to each other:
chuck Dana
Now, we solve for x
(which would be Dana's speed):
Cross-multiply:
185x= 160(x+5)
distribute :
185x= 160z+800
subtract 160x from both sides:
25x=800
divide both sides by 25:
x=32 mi/h
Remember that Chuck's speed is:
v
Chuck
=
x
+
5
so
vChuck = 32mi/h+5mi/h= 37 mi/h
