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3 years ago

Please help me find the difference and tell me what to type, i will mark brainliest

Mathematics

1 answer:

frez [133]3 years ago

4 0

Answer:

g^3 - 7

Step-by-step explanation:

write

(2g^2+3g-8)-(5g+1)

(5g^3-8)-(5g+1)

and then you get g^3 - 7

sorry if it is not write but it should be

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200 cans of food were distributed to 3 charity homes. 2/5 of the cans were given to the first home, 1/3 of the remainder to the

Mrrafil [7]

I believe 80 cans were given

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3 years ago

“Write five sentences about proportional relationships”

ivolga24 [154]

Answer:

Now, we’re going to consider an example of proportional relationship in our everyday life: When we put gas in our car, there is a relationship between the number of gallons of fuel that we put in the tank and the amount of money we will have to pay. In other words, the more gas we put in, the more money we’ll pay.

Step-by-step explanation:

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7 0

2 years ago

Read 2 more answers

what is the algebraic equation 3 times the sum of a number and 7 is 2 less than five times the number

stealth61 [152]

Let n = number

"3 times the sum of a number and 7" translates to 3(n + 7)

"2 less than five times the number" translates to 5n - 2

The word "is" becomes the equals sign.

3(n + 7) = 5n - 2

I think you already asked this one.

7 0

3 years ago

Factor completely 2x3 + x2 - 18x - 9

melisa1 [442]

Factor the following:
2 x^3 + x^2 - 18 x - 9

Factor terms by grouping. 2 x^3 + x^2 - 18 x - 9 = (2 x^3 + x^2) + (-18 x - 9) = x^2 (2 x + 1) - 9 (2 x + 1):
x^2 (2 x + 1) - 9 (2 x + 1)

Factor 2 x + 1 from x^2 (2 x + 1) - 9 (2 x + 1):
(2 x + 1) (x^2 - 9)

x^2 - 9 = x^2 - 3^2:
(2 x + 1) (x^2 - 3^2)

Factor the difference of two squares. x^2 - 3^2 = (x - 3) (x + 3):

Answer: (x - 3) (x + 3) (2 x + 1) thus the Answer is C.

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3 years ago

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The sequence$$1,2,1,2,2,1,2,2,2,1,2,2,2,2,1,2,2,2,2,2,1,2,\dots$$consists of $1$'s separated by blocks of $2$'s with $n$ $2$'s i

kicyunya [14]

Consider the lengths of consecutive 1-2 blocks.

block 1 - 1, 2 - length 2

block 2 - 1, 2, 2 - length 3

block 3 - 1, 2, 2, 2 - length 4

block 4 - 1, 2, 2, 2, 2 - length 5

and so on.

Recall the formula for the sum of consecutive positive integers,

$\displaystyle \sum_{i=1}^j i = 1 + 2 + 3 + \cdots + j = \frac{j(j+1)}2 \implies \sum_{i=2}^j = \frac{j(j+1) - 2}2$

Now,

$1234 = \dfrac{j(j+1)-2}2 \implies 2470 = j(j+1) \implies j\approx49.2016$

which means that the 1234th term in the sequence occurs somewhere about 1/5 of the way through the 49th 1-2 block.

In the first 48 blocks, the sequence contains 48 copies of 1 and 1 + 2 + 3 + ... + 47 copies of 2, hence they make up a total of

$\displaystyle \sum_{i=1}^48 1 + \sum_{i=1}^{48} i = 48+\frac{48(48+1)}2 = 1224$

numbers, and their sum is

$\displaystyle \sum_{i=1}^{48} 1 + \sum_{i=1}^{48} 2i = 48 + 48(48+1) = 48\times50 = 2400$

This leaves us with the contribution of the first 10 terms in the 49th block, which consist of one 1 and nine 2s with a sum of $1+9\times2=19$ .

So, the sum of the first 1234 terms in the sequence is 2419.

8 0

2 years ago