The midpoint of (x1,y1) and (x2,y2) is

just average them
(4,1) and (-2,4)
the midpoint is

(1,-1.5)
Answer:
<h2> 18.3</h2>
Step-by-step explanation:
from cosines theorem:
t² = 11² + 14² - 2•11•14•cos87°
t² = 121 + 196 + 308•0.05236
t² = 333.12688
t = √333.12688
t = 18.2517... ≈ 18.3
Answer:
25 in x 15 in
Step-by-step explanation:
Given:
- Length = 3/5 the width
- Area = 375 in²
Let width = 
Therefore, length = 3/5 
First create an equation for the area of the picture based on the given information for its width and length:

We are told the area of the enlarged picture is 375 in². Therefore, substitute this into the equation and solve for
to find the width of the enlarged picture:

Therefore, the width of the enlarged picture is 25 in.
Substitute the found value of
into the expression for length to find the length of the enlarged picture:

Therefore, the dimensions of the enlarged picture are <u>25 in x 15 in</u>. The width is 25 in and the length is 15 in, as the length is 3/5 of the width.
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