Answer:
82.79MPa
Step-by-step explanation:
Minimum yield strength for AISI 1040 cold drawn steel as obtained from literature, Sᵧ = 490 MPa
Given, outer radius, r₀ = 25mm = 0.025m, thickness = 6mm = 0.006m, internal radius, rᵢ = 19mm = 0.019m,
Largest allowable stress = 0.8(-490) = -392 MPa (minus sign because of compressive nature of the stress)
The tangential stress, σₜ = - ((r₀²p₀)/(r₀² - rᵢ²))(1 + (rᵢ²/r²))
But the maximum tangential stress will occur on the internal diameter of the tube, where r = rᵢ
σₜₘₐₓ = -2(r₀²p₀)/(r₀² - rᵢ²)
p₀ = - σₜₘₐₓ(r₀² - rᵢ²)/2(r₀²) = -392(0.025² - 0.019²)/2(0.025²) = 82.79 MPa.
Hope this helps!!
<u>Answer:</u>
<u>Explanation:</u>
We are given product of two consecutive odd integers is equal to 72.
Let one integer be x , then since these are consecutive and odd so the other integer will be equal to x + 1.
Their product is equal to 72. So,
x * (x + 1) = 72
=> 
=> is the required quadratic equation.
B. is the answer I believe since most are not functions
Answer:
i dont understan the method you gave me can youbplease ask again showing a different method
I got 6x+3
The three equations are:
(2x-6) + (3x+1) + (x+8) =perimeter
2x+3x+x/1x=6x
-6+1+8= 3
