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faust18 [17]
4 years ago
6

Help please !! 20 points

Mathematics
1 answer:
Readme [11.4K]4 years ago
8 0
For the table 0.2 would be (1/5) 0.5 would be (1/2). And 0.7 would be (7/10).


For number 2 I would say the denominator changed each time
You might be interested in
Suppose the function of h is defined, for all real numbers as follows: (f) x = -3 if x is <) 3 if x is =0 -2 if x is > 0
V125BC [204]

Answer:

See explanation

Step-by-step explanation:

The question is not properly presented; I will answer this with the following similar question.

h(x) = -\frac{1}{3}x^2 + 4 --- x \ne 2

h(x) = -4 --- x= 2

Required

h(-5)\ \&\ h(2)

<u>Calculating h(-5)</u>

This implies that: x = -5

-5 \ne 2

So, we make use of:

h(x) = -\frac{1}{3}x^2 + 4

Substitute -5 for x

h(-5) = -\frac{1}{3} * (-5)^2 + 4

h(-5) = -\frac{1}{3} * 25 + 4

h(-5) = -\frac{25}{3} + 4

Take LCM

h(-5) = \frac{-25+12}{3}

h(-5) = -\frac{13}{3}

<u>Calculating h(2)</u>

This implies that: x = 2

2 = 2

So, we make use of:

h(x) = -4

Substitute 2 for x

h(2) = -4

<em>Use the above explanation to answer your question</em>

3 0
3 years ago
*2. For each of the following discriminant state what it indicates about the number of
n200080 [17]

Answer:

b. b² - 4ac = 0

8 0
2 years ago
Somebody please help me:(
Varvara68 [4.7K]
How do you need help?
3 0
3 years ago
Read 2 more answers
Terry rectangular yard is 15 meters by 18 meters Todd's rectangular yard is 20 meters by 9 meters how much greater is the area o
mariarad [96]

Answer:

Terry's yard is greater than Todd's yard by 90 square meters.

Step-by-step explanation:

We are given the following in the question:

Terry's yard dimensions:

Length,l = 18 meters

Width,w = 15 meters

Area of Terry's yard =

A = l\times w\\A = 18\times 15\\A=270\text{ square meters}

Todd's yard dimensions:

Length,l = 20 meters

Width,w = 9 meters

Area of Todd's yard =

A = l\times w\\A = 20\times 9\\A=180\text{ square meters}

Thus, Terry's yard is greater than Todd's yard.

Difference in area of yards

= Terry's yard area - Todd's yard area

=270-180\\=90\text{ squarde meters}

Thus, Terry's yard is greater than Todd's yard by 90 square meters.

8 0
3 years ago
Calculate the standard deviation of the following data. 3, 4, 5, 6, 2, 3, 12, 79, 5
malfutka [58]
The answer to this is 23.42 (For population, SD)

The data given as a whole is called UNGROUPED data. The standard deviation can be computed with the formula: 

\sqrt{\dfrac{\sum(x_i-\bar{x})^2}{n}}

To do this, you need to first figure out the following:

Mean (\bar{X}) =?
The sum of \sum(x_i-\bar{X})^{2} =?

You need to write down your data in a table, but before you can do this, you need to first find out what the mean is and you can do this by adding up all the data and dividing it by the number of observations:

\bar{X} = \frac{sum of all data}{number of observations}
\bar{X} = \frac{3+4+5+6+2+3+12+79+5}{9} = \frac{119}{9}= 13.22

So we subtract the mean from each data to fill in the second column. I'll use the first raw data to make the first row as an example here:
(x-\bar{X}= 3-13.22=-10.22) 

For the third column, you just need get the square of the second column.
(x_i-\bar{X})^{2} =(-10.22)^{2}= 104.4484

For this table, let x be raw data and X be \bar{X}:

  x   |    (x-X)        |    (x-X)²     
  3   |    -10.22     |   104.4484         
       |                   |
  4   |   -  9.22      |     85.0084
       |                   |
  5   |   -  8.22      |     67.5684
       |                   |
  6   |   -  7.22      |     52.1284
       |                   |
  2   |     - 11.22   |     125.8884
       |                   |
  3   |    -10.22     |     104.4484
       |                   |
12   |   -  1.22      |         1.4884 
       |                   |
79   |    65.78      |   4327.0084
       |                   |
 5    |    -  8.22     |       67.5684
                 
REMEMBER: The Σ means "the sum of" to get Σ(x-X)² Add the values in the third column to get the sum of (x-X)² and you will get 4,935.5556 

Now all you have to do is input it into your equation:

sd=\sqrt{\dfrac{\sum(x_i-\bar{x})^2}{n}}
\sqrt{\frac{4935.5556}{9}}
\sqrt{548.39506666}
23.42

The standard deviation is 23.42

4 0
4 years ago
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