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faust18 [17]
3 years ago
6

Help please !! 20 points

Mathematics
1 answer:
Readme [11.4K]3 years ago
8 0
For the table 0.2 would be (1/5) 0.5 would be (1/2). And 0.7 would be (7/10).


For number 2 I would say the denominator changed each time
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Uptown Country Club only admits members with annual incomes in the top 2.5% of the United States. If the annual individual incom
Verdich [7]

Answer:

$74,600

Step-by-step explanation:

-Given the probability is 2.5%, mean=$55,000 and standard deviation= $10,000

-We find the z value of 2.5%

p=P(z>\frac{X-\mu}{\sigma})\\\\1.96=P(z

Hence, the minimum amount of income to be in the top 2.5% is $74,600

5 0
3 years ago
Express XCVI to Hindu Arabic<br>numerals.​
ozzi

Answer:

XCVI in Hindu Arabic  numerals.​ is 96 (100-10+5+1)

6 0
3 years ago
A computer system uses passwords that are six characters, and each character is one of the 26 letters (a–z) or 10 integers (0–9)
Blababa [14]

First of all, since we have 36 characters available per spot (26 letters and 10 digits), and we have 6 spots, we have a total of

36^6

possible passwords.

Event A happens if the password starts with either a, e, i, o or u. If we fix the first character, we're left with 36 characters available for each of the remaining 5 spots, leading to a total of

5\cdot 36^5

possible passwords.

So, the probability of event A, computed as the ratio between "good" cases and all possible cases, is

\dfrac{5\cdot 36^5}{36^6}=\dfrac{5}{36}

Event B works exactly the same, since we're fixing the last spot, leaving 36 characters available for each of the first 5 spots. So, we have

P(A)=P(B)=\dfrac{5}{36}

As for the intersection, we want the first character to be a vowel, and the last character to be an even digits. There are 25 passwords satisfying this request:

axxxx0,\ axxxx2,\ axxxx4,\ axxxx6,\ axxxx8

exxxx0,\ exxxx2,\ exxxx4,\ exxxx6,\ exxxx8

ixxxx0,\ ixxxx2,\ ixxxx4,\ ixxxx6,\ ixxxx8

oaxxxx0,\ oxxxx2,\ oxxxx4,\ oxxxx6,\ oxxxx8

uxxxx0,\ uxxxx2,\ uxxxx4,\ uxxxx6,\ uxxxx8

Where x can be any of the 36 characters.

So, we have 25 cases with 4 vacant slots, leading to a probability of

P(A\cap B)=\dfrac{25\cdot 36^4}{36^6}=\dfrac{25}{1296}

Finally, you can compute the probability of the union using the formula

P(A\cup B)=P(A)+P(B)-P(A\cap B)

Since we already computed all these quantities.

7 0
3 years ago
90% of 250 please help ​
Anna007 [38]
I agree the answer is 225 and you can also use the calculator too.
6 0
3 years ago
2) It is a subset of a line consisting of two endpoints and all the points in between.
STALIN [3.7K]

Answer:

b.line segment

Step-by-step explanation:

line segment is a piece and or part of a line having two end points

6 0
3 years ago
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