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2 years ago

Can you help me in write the perimeter of the triangle in a simplest form

Mathematics

1 answer:

Angelina_Jolie [31]2 years ago

8 0

I got 6x+3

The three equations are:

(2x-6) + (3x+1) + (x+8) =perimeter

2x+3x+x/1x=6x

-6+1+8= 3

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Factor 10x^3 8x^2 - 6x. (<br> a.2x(5x 4x - 3) (<br> b.2x(5x 4x^2- 3) (<br> c.2x(5x^2 4x - 3)

Semmy [17]

You have to look at the equation and find a common factor bettween all parts. SO, we see they all have an x, so that is the first thing you can factor out. They also have
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4 0

3 years ago

If sin(x) = 5/13, and x is in quadrant 1, then tan(x/2) equals what?

Rufina [12.5K]

$x$ is in quadrant I, so $0$ , which means $0$ , so $\dfrac x2$ belongs to the same quadrant.

Now,

$\tan^2\dfrac x2=\dfrac{\sin^2\frac x2}{\cos^2\frac x2}=\dfrac{\frac{1-\cos x}2}{\frac{1+\cos x}2}=\dfrac{1-\cos x}{1+\cos x}$

Since $\sin x=\dfrac5{13}$ , it follows that

$\cos^2x=1-\sin^2x\implies \cos x=\pm\sqrt{1-\left(\dfrac5{13}\right)^2}=\pm\dfrac{12}{13}$

Since $x$ belongs to the first quadrant, you take the positive root ( $\cos x>0$ for $x$ in quadrant I). Then

$\tan\dfrac x2=\pm\sqrt{\dfrac{1-\frac{12}{13}}{1+\frac{12}{13}}}$

$\tan x$ is also positive for $x$ in quadrant I, so you take the positive root again. You're left with

$\tan\dfrac x2=\dfrac15$

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3 years ago

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Volgvan

They no more cause 3-

7 0

3 years ago

Which ordered pair is a solution of the equation? 5x-2y=18

irakobra [83]

Answer:

(2, -4)

Step-by-step explanation:

I did some research.

Plz click the Thanks button!

<Jayla>

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2 years ago

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qwelly [4]

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2 years ago