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Marta_Voda [28]
3 years ago
5

A website sells a dress at £40 and shoes at £32. The website has an offer: Buy a dress and shoes together and get 1/2 off the pr

ice. There is also a shipping and handling charge of £4 added at the end, after any discount. If Ruth buys both a dress and shoes, how much will she actually pay?
Mathematics
1 answer:
tekilochka [14]3 years ago
6 0

Answer:

\pounds36

Step-by-step explanation:

Cost of one dress = \pounds40

Cost of one pair of shoes = \pounds32

Cost of one dress and a pair of shoes is 40+32=\pounds72

They get half off the price because they buy both

\dfrac{72}{2}=\pounds32

The shipping and handling charge is \pounds4.

So, the total amount Ruth has to pay is 32+4=\pounds36.

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Mr Stevenson has 160 cows goats horses and chickens on his farm 19 percent of the animals are cows 28 percent goats 13 percent h
castortr0y [4]

Answer:

64 Chickens

Step-by-step explanation:

1. Add up the percents

19% + 28% + 13% = 60%

2. Subtract from 100%

100% - 60% = 40%

3. Multiply the total number of animals by the percent of chickens

160 * .4 = 64 Chickens



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3 years ago
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Estimate the instantaneous rate of change of P(t) = 2t² + 3 at the point t = – 3
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2 years ago
1. In an auditorium, there are 21 seats in the first row and 26 seats in the second row. The number of seats in a row continues
kondor19780726 [428]
1. Let s_n be the number of seats in the n-th row. The number seats in the n-th row relative to the number of seats in the (n-1)-th row is given by the recursive rule

s_n=s_{n-1}+5


Since s_1=21, we have

s_2=s_1+5
s_3=s_2+5=s_1+2\cdot5
s_4=s_3+5=s_1+3\cdot5
\cdots
s_n=s_{n-1}+5=\cdots=s_1+(n-1)\cdot5

So the explicit rule for the sequence s_n is

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In the 15th row, the number of seats is


s_{15}=5(15)+16=91

2. Let p_n be the amount of profit in the n-th year. If the profits increase by 6% each year, we would have

p_2=p_1+0.06p_1=1.06p_1
p_3=1.06p_2=1.06^2p_1
p_4=1.06p_3=1.06^3p_1
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p_n=1.06p_{n-1}=\cdots=1.06^{n-1}p_1

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The second part of the question is somewhat vague - are we supposed to find the profits in the 20th year alone? the total profits in the first 20 years? I'll assume the first case, in which we would have a profit of


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3. Now let p_n denote the number of pushups done in the n-th week. Since 3\cdot4=12, 12\cdot4=48, and 48\cdot4=192, it looks like we can expect the number of pushups to quadruple per week. So,

p_n=4p_{n-1}

starting with p_1=3.

We can apply the same reason as in (2) to find the explicit rule for the sequence, which you'd find to be

p_n=4^{n-1}p_1\implies p_n=4^{n-1}\cdot3
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