C is the answer because the X factors can’t repeat
Answer:
The total surface area of this box is 62.14 square feet
Step-by-step explanation:
Given:
Length = 3.5 feet
Width = 2.2 feet
Height = 4.1 feet
To Find:
The Surface area of the prism = ?
Solution:
The box is the shape of rectangular prism
Then the surface area of the prism = 2(lh +hw +wl)
Where
l is the length
w is the width
h is the height
Substituting the values
The surface area of the prism =
The surface area of the prism = 2(14.35 + 9.02 + 7.7)
The surface area of the prism = 2(31.07)
The surface area of the prism = 62.14 square feet
If the length of rectangular school hall is 4 times the width and the perimeter be 55m, then the length is 22m and the width of the school hall be 5.5m.
Given that the length of rectangular school hall is 4 times the width.
We are required to find the length and breadth of the rectangle which has the length be 4 times the width.
Perimeter of rectangle is the sum of all the length and breadth of that rectangles.
Perimeter of rectangle is given as 55m
Perimeter=2(L+B)
let the width of rectangle be x.
Length of that rectangle be 4x.
According to question,
2(x+4x)=55
2*5x=55
10x=55
x=55/10
x=5.5 m
Width be 5.5 m.
Length of rectangle be 4*5.5=22m.
Hence if the length of rectangular school hall is 4 times the width then the length is 22m and the width of the school hall be 5.5m.
Learn more about perimeter at brainly.com/question/19819849
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Answer:
3cm/s
Step-by-step explanation:
Area of a square is expressed as:
A = L²
Rate of change of area is expressed as:
dA/dt = dA/dL•dL/dt
Given that
dA/dt = 24cm²/s
L = 4cm
Required
dL/dt
Since dA/dl = 2L
dA/dl = 2(4)
dA/dl = 8cm
Subatitute the given values into the formula
24 = 8 dL/dt
dL/dt = 24/8
dL/dt = 3cm/s
