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suter [353]
2 years ago
7

The length of rectangular a school hall is 4 times the width and the perimeter is 55m. what is the: width: length:

Mathematics
1 answer:
tangare [24]2 years ago
6 0

If the length of rectangular school hall is 4 times the width and the perimeter be 55m, then the length is 22m and the width of the school hall be 5.5m.

Given that the length of  rectangular school hall is 4 times the width.

We are required to find the length and breadth of the rectangle which has the length be 4 times the width.

Perimeter of rectangle is the sum of all the length and breadth of that rectangles.

Perimeter of rectangle is given as 55m

Perimeter=2(L+B)

let the width of rectangle be x.

Length of that rectangle be 4x.

According to question,

2(x+4x)=55

2*5x=55

10x=55

x=55/10

x=5.5 m

Width be 5.5 m.

Length of rectangle be 4*5.5=22m.

Hence if the length of rectangular school hall is 4 times the width then the length is 22m and the width of the school hall be 5.5m.

Learn more about perimeter at brainly.com/question/19819849

#SPJ4

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ivolga24 [154]

Answer:

w=V/(lh)

Step-by-step explanation:

Let

l------> the length of the base of the prism

w------> the width of the base of the prism

h------> the height of the prism

we know that

The volume of the prism is equal to

V=lwh

Solve for w

That means-------> isolate the variable w

so

Divide both sides by (lh)

V/(lh)=lwh/(lh)

Simplify

w=V/(lh)

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Answer:

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Anwar is thinking of a number. He gives three clues about his number: It is an odd number; The number is less than -12; and The
tigry1 [53]

Answer:

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Step-by-step explanation:

it must be either -11 or -13. -13 is less  than -12.

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3 years ago
What is the value of x?
Lerok [7]
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3 years ago
For two events and , the probability that occurs is 0.8, the probability that occurs is 0.4, and the probability that both occur
sergey [27]

Answer:

P(B|A)=0.25  , P(A|B) =0.5

Step-by-step explanation:

The question provides the following data:

P(A)= 0.8

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Since the question does not mention which of the conditional probabilities need to be found out, I will show the working to calculate both of them.

To calculate the probability that event B will occur given that A has already occurred (P(B|A) is read as the probability of event B given A) can be calculated as:

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      = (0.2) / (0.8)  

P(B|A)=0.25

To calculate the probability that event A will occur given that B has already occurred (P(A|B) is read as the probability of event A given B) can be calculated as:

P(A|B) = P(A∩B)/P(B)

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4 years ago
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