Can someone please help me f(x) = -3x + 20; f(8)
2 answers:
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<h2>Answer and Explanation to questions 13,14,15</h2>
13) as given in the question.
14) Since Y is the midpoint of XZ. So, Y will divide XZ in equal halves into XY and YZ.
15)
and
. So,
∠3 is supplementary to ∠1 means: ∠3 + ∠1 = 180°
And, according to figure ∠1 + ∠2 = 180° as ∠1 and ∠2 form a straight line.
∠3 + ∠1 = 180° .............(i)
∠1 + ∠2 = 180° .............(ii)
subtracting equation (i) and (ii) will give ∠3 = ∠2 ..........(iii)
15) ∠3 is supplementary to ∠1 as given in the question
16) ∠2 is supplementary to ∠1 as shown be equation (ii)
18) ∠3 ≅ ∠2 as shown by equation (iii)
<h2>Answer and Explanation to questions 19</h2>∠3 and ∠4 form a straight line. Therefore, ∠3 + ∠4 = 180° .......(i)
∠4 and ∠5 form a straight line. Therefore, ∠4 + ∠5 = 180° .......(ii)
subtracting equation (i) and (ii)
∠3 + ∠4 - (∠4 + ∠5) = 180°-(180°)
∠3 + ∠4 - ∠4 - ∠5 = 180°-180°
∠3 - ∠5 = 0
∴ ∠3 = ∠5 (Hence Proved)
Answer:
Step-by-step explanation:
The best way to do this is to use your LCM and eliminate the fractions. To find the LCM you have to use all the denominators as a multiplier so the denominator in each term cancels out. We will first factor the x-squared term to simplify and see what 2 factors are hidden there.
factors to (x + 2)(x - 2). That means that our 3 denominators that make up our LCM are x(x+2)(x-2). We will mulitply that in to each term in our rational equation, canceling out the denominators where applicable.
In the first term, the (x-2) will cancel leaving us with
x(x+2)[2] which simplifies to
In the second term, the (x+2)(x-2) cancels out leaving us with
x[7].
In the last term, the x cancels out leaving us with
(x+2)(x-2)[5] which simplifies to
Now we will distribute through each cancellation:
2x²+4x;
7x;
5x²-20
Putting them all together we have
2x² + 4x + 7x = 5x² - 20
Combining like terms gives us a quadratic:
3x² - 11x - 20 = 0
Factor that however you find it easiest to factor quadratics and get that
x = 5 and x = -4/3