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nekit [7.7K]
3 years ago
15

Please help me!! Use synthetic division

Mathematics
1 answer:
Leokris [45]3 years ago
4 0
I believe the 3rd one
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If 3x + 2 = 4, what is the value of 6x – 4?
Andreas93 [3]

Answer:

0

Step-by-step explanation:

3x = 2

x = 2/3

plug in

12/3 - 4

4 - 4

=0

4 0
2 years ago
According to a college survey, 22% of all students work full time. Find the standard deviation for the random variable X, the nu
mixer [17]

Answer:

1.66

Step-by-step explanation:

Calculation to find the standard deviation for the random variable X of the number of students who work full time in samples of size

Using this formula

Standard deviation(X)=√np(1−p)

Where,

n represent the number of students=16

p represent the percentage of all students who work full time=22

Let plug in the formula

Standard deviation(X)=√16(0.22)(1−0.22)

Standard deviation(X)=√(3.52)(0.78)

Standard deviation(X)=√2.7456

Standard deviation(X)=1.656

Standard deviation(X)=1.66 (Approximately)

Therefore the standard deviation for the number of students who work full time in samples of size 16 will be 1.66

8 0
3 years ago
Which 2 teams scored a total of 100 points, red has 29 points, yellow has 38 points, Green has 41 points, blue has 76 points ora
Bess [88]

Answer:

Blue and Black

Step-by-step explanation:

hi! i think you're asking which of the 2 teams' points added together equal 100. if so, it would be blue and black because 76 + 24 = 100.

broken down: 70 + 20 = 90, 6 + 4 = 10, 90 + 10 = 100 :)

hope i understood this right!

6 0
3 years ago
Which graph shows the rotation of the shape above, 90° counterclockwise about the origin?​
lara31 [8.8K]

Answer:

W

Step-by-step explanation:

the rule of a 90⁰ counterclockwise rotation is (x,y) -> (-y,x)

For example, if you rotated a point at (3,2) by 90⁰ counterclockwise. You would change it to (-2,3).

5 0
3 years ago
The following data were collected from 12 rain gauges in a park. Build a 95% CI for the mean rainfall at the park.
dybincka [34]

Answer:

Critical values:t_{\alpha/2}=-2.201 t_{1-\alpha/2}=2.201

95% confidence interval would be given by (3.646;4.472)

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The data is:

4.65 3.89 2.73 4.35 3.80 4.86 4.33 4.37 4.76 4.05 3.05 3.87

2) Compute the sample mean and sample standard deviation.

In order to calculate the mean and the sample deviation we need to have on mind the following formulas:  

\bar X= \sum_{i=1}^n \frac{x_i}{n}

s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}}

=AVERAGE(4.65,3.89,2.73, 4.35, 3.8, 4.86, 4.33, 4.37, 4.76, 4.05, 3.05, 3.87)

On this case the average is \bar X= 4.059

=STDEV.S(4.65,3.89,2.73, 4.35, 3.8, 4.86, 4.33, 4.37, 4.76, 4.05, 3.05, 3.87)

The sample standard deviation obtained was s=0.6503

3) Find the critical value t* Use the formula for a CI to find upper and lower endpoints

In order to find the critical value we need to take in count that our sample size n =12 <30 and on this case we don't know about the population standard deviation, so on this case we need to use the t distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. The degrees of freedom are given by:

df=n-1=12-1=11

We can find the critical values in excel using the following formulas:

"=T.INV(0.025,11)" for t_{\alpha/2}=-2.201

"=T.INV(1-0.025,11)" for t_{1-\alpha/2}=2.201

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}  

And we can use Excel to calculate the limits for the interval

Lower interval : "=4.059 -2.201*(0.6503/SQRT(12))" =3.646

Upper interval :  "=4.059 +2.201*(0.6503/SQRT(12))" =4.472

So the 95% confidence interval would be given by (3.646;4.472)

8 0
3 years ago
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