Answer:
Quadrant III
Step-by-step explanation:
Quadrant I -> (+x,+y)
Quadrant II -> (-x,+y)
Quadrant III -> (-x,-y)
Quadrant IV -> (+x,-y)
If x and y must both be less than 0, then they must both be negative. Therefore, Quadrant III is your answer.
Answer:
Step-by-step explanation:
hello :
f(x)=3x^2-6x+13
1) a=3 and b= -6
2) the x coordinate of the vertex is : x= -b/2a so : x= -(-6)/6 = 1
3) the y coordinate by x= 1 is : f(1) = 3(1)²-6(1)+13 = 10
We have the equations: l = 2b and 2l + 2b = 228;
Then, 4b + 2b = 228;
6b = 228;
b = 228/6;
b = 38 (breadth);
l = 2·38;
l = 76 (length);
Answer:
4x^2-x/x^2+x-2
Step-by-step explanation:
What question??? (20 characters)
