Answer:
The length of the first piece = 41 cm
Step-by-step explanation:
Let the length of the first piece = a
Let the length of the second piece = b
Let the length of the third piece = c
we are given the following:
b = 3a . . . . . (1) (The 2nd piece is 3 times as long as the 1st piece)
c = 6 + a . . . . (2) (the 3rd piece is 6 centimeters longer than the 1st piece)
a + b + c = 211 . . . . . (3) ( the yarn has a total length of 211 centimeters)
Next, let us eliminate two variables, and this can easily be done by substituting the values of b and c in equations 1 and 2 into equation 3. this is done as follows:
a + b + c = 211
a + (3a) + (6 + a) = 211 ( remember that b = 3a; c = 6 + a)
a + 3a + 6 + a = 211
5a + 6 = 211
5a = 211 - 6 = 205
5a = 205
∴ a = 205 ÷ 5 = 41 cm
a = 41 cm
Therefore the length of the first piece (a) = 41 cm
now finding b and c
substituting a into equation 1 and 2
b = 3a
b = 3 × 41 = 123
∴ b = 123 cm
c = 6 + a
c = 6 + 41 = 47
∴ c = 47 cm
Answer:
here's the solution : -
=》2x - 3y = -29
=》x + 6y = 23
=》x = 23 - 6y
now, plugging the value of x in equation 1, we get : -
=》2x - 3y = -29
=》2 (23 - 6y) - 3y = - 29
=》46 - 12y - 3y = -29
=》-15y = -29 - 46
=》y = -75 ÷ -15
=》y = 5
now, plugging the value of y as 5 in equation 2
=》x + 6y = 23
=》x + (6 × 5.2) = 23
=》x = 23 - 30
=》x = - 7
The answer is 54 degrees I took the exam I got it right
Step-by-step explanation:
Let the height above which the ball is released be H
This problem can be tackled using geometric progression.
The nth term of a Geometric progression is given by the above, where n is the term index, a is the first term and the sum for such a progression up to the Nth term is
To find the total distance travel one has to sum over up to n=3. But there is little subtle point here. For the first bounce ( n=1 ), the ball has only travel H and not 2H. For subsequent bounces ( n=2,3,4,5...... ), the distance travel is 2×(3/4)n×H
a=2H..........r=3/4
However we have to subtract H because up to the first bounce, the ball only travel H instead of 2H
Therefore the total distance travel up to the Nth bounce is
For N=3 one obtains
D=3.625H
Answer:
1,3,5,7,9....up to soon are odd numbers
Step-by-step explanation:
they are not divided by 2
