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8_murik_8 [283]
3 years ago
11

Walking down a pebble beach becomes less painful as you enter the sea. Explain why.

Physics
1 answer:
SVEN [57.7K]3 years ago
4 0

Answer:Since pressure = force/area, the same force on a smaller area means more pressure. When you are walking on sand, the force being applied by your body is spread out over the entire surface of your foot. ... So, more pressure applied on a given area of your foot causes more pain.

Explanation:

Good Question

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EXPLAIN how energy changes and is distributed as it moves from level to the next in a food chain.
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Answer: There is a smaller amount of energy consumed making the consumer eat more

Explanation:

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Two rigid rods are oriented parallel to each other and to the ground. The rods carry the same current in the same direction. The
IRISSAK [1]

To develop this problem we will apply the concepts related to the Electromagnetic Force. The magnetic force can be defined as the product between the free space constant, the current (of each cable) and the length of these, on the perimeter of the cross section, in this case circular. Mathematically it can be expressed as,

F= \frac{\mu_0}{2\pi} \frac{I^2L}{d}

Here,

\mu_0 = Permeability free space

I = Current

L = Length

d= Distance between them

Our values are,

L = 0.67m

m = 0.082kg

d = 7.4*10^{-3}m

I = \text{Current through each of the wires}

Rearranging the previous equation to find the current,

\frac{mg}{L} = 2*10^{-7} (\frac{I^2}{d})

I = \sqrt{\frac{mgd}{(2*10^{-7})L}}

I = \sqrt{\frac{(0.082)(9.8)(7.4*10^{-3})}{(2*10^{-7})(0.67)}}

I = \sqrt{44377.9}

I = 210.66A

Therefore the current in the rods is 210.6A

8 0
4 years ago
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On what factors, current sensitivity voltage sensitivity of<br>a galvanometer depend?​
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7 0
3 years ago
A reciprocating compressor is a device that compresses air by a back-and-forth straight-line motion, like a piston in a cylinder
QveST [7]

Answer:

\Delta \theta = 47.57^{\circ} C

Explanation:

given,

moles of air compressed, n = 1.70 mol

initial temperature, T₁ = 390 K

Power supply by the compressor, P = 7.5 kW

Heat removed = 1.3 kW

Angular frequency of the compressor, f = 110 rpm = 110/60 = 1.833 rps.

Time of compression = time of the hay revolution

             =\dfrac{1}{2}\ T

             =\dfrac{1}{2}\times \dfrac{1}{f}

             =\dfrac{1}{2}\times \dfrac{1}{1.833}

             =0.273 s

Using first law of thermodynamics

U = Q - W

now,

\dfrac{\Delta U}{\Delta t} = \dfrac{\Delta Q}{\Delta t}- \dfrac{\Delta W}{\Delta t}

Power supplied \dfrac{\Delta W}{\Delta t} = 7.5 kW

heat removed \dfrac{\Delta Q}{\Delta t} = 1.3 kW

now,

\dfrac{\Delta U}{\Delta t} = 7.5 -1.3

\dfrac{\Delta U}{\Delta t} = 6.2 kW

we know,

\dfrac{\Delta U}{\Delta t}=\dfrac{nC_v\Delta \theta}{\Delta t}

 C_v for air = 5 cal/° mol

                   = 5 x 4.186 J/mol°C  = 20.93 J/mol°C

now,

\Delta \theta = \dfrac{\Delta U}{\Deta t}\times \dfrac{\Delta t}{n C_v}

\Delta \theta = 6.2\times 10^3 \times \dfrac{0.273}{1.7\times 20.93}

\Delta \theta = 47.57^{\circ} C

the temperature change per compression stroke is equal to 47.57°C.

4 0
3 years ago
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