Answer:
During <u>winter (late December/early January)</u> the Earth is closest to the Sun and during <u>summer (late June/early July)</u> the Earth is farthest from the Sun.
Explanation:
In the northern hemisphere, the earth usually comes closer to the sun during the time of winter season, mostly in late December or early January.
On the other hand, the earth is farthest from the sun during the time of summer season, mostly in late June or early July.
When the earth is closer to the sun, during the winter, it is comparatively cold. It is due to the absorption of a lesser amount of incoming solar radiation. The tilt of the earth is also responsible for this low temperature.
But, when the earth is farthest from the sun, during the summer, it is comparatively hot. It is due to the absorption of a large amount of incoming solar radiation.
<span>LOCATION Z, because it is only 2 away from the coast.
The rest are farther inland
hope this helps</span>
Answer:
d = 1.954 Km
Explanation:
given,
total distance, D = 2.5 Km
in stretch A to B =
speed = 99 Km/h = 99 x 0.278 = 27.22 m/s time =t
in stretch B to C
time = 3.4 s
In stretch C to D
speed = 48 Km/h = 48 x 0.278 = 13.34 m/s time =t
we know,
distance = speed x time
distance of BC
using equation of motion
v = u + a t
27.22 = 13.34 - a x 3.4
a = 4.08 m/s²
uniform deceleration is equal to 4.08 m/s²
distance traveled in BC
s = 68.94 m
3000 = 27.5 t + 68.94 + 13.33 t
40.83 t = 2931.06
t = 71.79 s
distance travel in AB
distance = s x t
d = 27.22 x 71.79
d = 1954 m
d = 1.954 Km
distance between A and B is equal to 1.954 Km.
Before solving this question, first we have to understand the special theory of relative.
As per classical mechanics, the velocity of light will be different in different frame of reference. The light moves in the ether medium which exists every where in the entire universe.
Let us consider a body which moves with a velocity v. Let light is coming along the direction of the body. As per classical mechanics,the velocity of light with respect to the body will be [ c-v].
Let us consider that light is coming from opposite direction. Hence, the velocity of light with respect to the observer will be c+v.
From above we see that velocity of light is different in both the cases which is wrong.
As per Einstein's special theory of relativity, the velocity of light will be same in every frame of reference i.e c=300000 km/s.
As per the question ,the space craft is moving with a velocity 0.1 c.
We are asked to calculate the velocity of the light with respect to an observer present in Mars.
Considering Einstein's theory of relativity, the velocity of light will be c [300000 km/s] with respect to the person in Mars.
I believe that it is true! :)
