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dmitriy555 [2]
3 years ago
5

If Rupert does all his math quizzes, and if he scores 4 correct for every 5 questions, what will his percentage correct be?

Mathematics
1 answer:
Sauron [17]3 years ago
5 0

Answer:

LOL IT'S GONNA BE 80%

Step-by-step explanation:

HOPE THIS HELPS, SORRY FOR ALL THE CAPS

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Which equations represent the line that is perpendicular to the line 5x − 2y = −6 and passes through the point (5, −4)? Select t
nignag [31]

For this case we have that by definition, the equation of a line in the slope-intersection form is given by:

y = mx + b

Where:

m: It's the slope

b: It is the cut-off point with the y axis

On the other hand we have that if two lines are perpendicular, then the product of their slopes is -1. So:

m_ {1} * m_ {2} = - 1

The given line is:

5x-2y = -6\\-2y = -6-5x\\2y = 5x + 6\\y = \frac {5} {2} x + \frac {6} {2}\\y = \frac {5} {2} x + 3

So we have:

m_ {1} = \frac {5} {2}

We find m_ {2}:m_ {2} = \frac {-1} {\frac {5} {2}}\\m = - \frac {2} {5}

So, a line perpendicular to the one given is of the form:

y = - \frac {2} {5} x + b

We substitute the given point to find "b":

-4 = - \frac {2} {5} (5) + b\\-4 = -2 + b\\-4 + 2 = b\\b = -2

Finally we have:

y = - \frac {2} {5} x-2

In point-slope form we have:

y - (- 4) = - \frac {2} {5} (x-5)\\y + 4 = - \frac {2} {5} (x-5)

ANswer:

y = - \frac {2} {5} x-2\\y + 4 = - \frac {2} {5} (x-5)

3 0
3 years ago
Read 2 more answers
The set of possible values of m is {5,7,9}. What is the set of possible values of k if 2k=m+3?
Paladinen [302]
Just plug in the values for m

so the possible values for k are
when m=5
2k=5+3 \\ k=4
when m=7
2k=7+3 \\ 
k=5
when m=9
2k=9+3 \\ k=6
so the possible values for k are {4,5,6}
4 0
3 years ago
You purchase two bottles of and a hat. The hat costs $6.50. You pay 6% sales tax. You pay a total of $16.43. How much does one b
Advocard [28]
$4.50.

Total with tax = 1.06x = 16.43
X = 15.50 = total before tax

15.50 - 6.50 = 9 = amount spent on both bottles.

9/2 = 4.5 = amount spent on one bottle.
8 0
3 years ago
Read 2 more answers
Consider firing a pumpkin from a canon at a target that is 17 meters away. The pumpkin follows a quadratic path as displayed to
bixtya [17]
A.
(0,00
(2.6,7.9)
(4.8,12.4)
(9.7,15.1)

b.
well, the points don't look like they are on the line but they actually are (plot twist)


so
since (0,0) is on th egarph

0=a(0)²+b(0)+c
0=c
so
f(x)=ax²+bx+0 or
f(x)=ax²+bx

find a and b
sub points

(2.6,7.9)
7.9=a(2.6)²+b(2.6)
7.9=6.76a+2.6b

(4.8,12.4)
12.4=a(4.8)²+b(4.8)
12.4=23.04a+4.8b

use those 2 equations
7.9=6.76a+2.6b
12.4=23.04a+4.8b

eliminate b
multiply first equation by -4.8 and 2nd by 2.6 and add them
-37.92=-32.448a-12.48b
32.24=59.904a-12.48b +
-5.68=27.456a+0b

-5.68=27.456a
divide both sides by 27.456
(-5.68/27.456)=a
find b

12.4=23.04a+4.8b
12.4=(-130.8672/27.456)+4.8b
12.4+(130.8672/27.456)=4.8b
(12.4+(130.8672/27.456))/4.8=b

da equation is
y= \frac{-5.68}{27.456} x^2+ \frac{12.4+\frac{130.8672}{27.456}}{4.8}x



c. the roots are found with your calculator
the roots are at x=0 and x=17.287323943662
so very close to the target but not exactly on it
if the target has a radius of 0.287323943662 or more then it will hit the target
5 0
3 years ago
What is 100 x 100 ...............
miskamm [114]
100 x 100............. = 10 000


7 0
3 years ago
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