Answer:
2(x+5)
Step-by-step explanation:
Answer:
1256
Step-by-step explanation:
Given the function F(x)=1256(1.24)^x, the initial value occurs at x = 0
Substitute x = 0 into the function;
F(0)=1256(1.24)^0
f(0) = 1256(1) (any value raise to sero is 1)
f(0) = 1256
hence the initial value is 1256
Well as x can never actually be -1 because I'm in the denominator -1 + 1 = 0 and we cannot divide by zero. But we can look at what number it approaches and i assume that is the relative value. sometimes functions will have asymptotes and others will have holes in the graph. this one would have an asymptote going down at a rapid rate. the asymptote would go on forever getting infinitely close to -1 but never touching. So I would say since the asymptote goes down forever that the graph approaches negative infinity
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