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vova2212 [387]
3 years ago
13

What would be the new value of a after running the program

Mathematics
1 answer:
Nitella [24]3 years ago
6 0

Answer:

15

Step-by-step explanation:

var a = 3

then a= 3

var b = 5

then b = 5

a ( a new variable ) = a * b = 3 * 5

You might be interested in
Solve the simultaneous equation.<br> 7a+3b=46<br> 4a+5b=69
irinina [24]

Answer:

a=1 and b=13

do you need the working out?

7 0
3 years ago
If a rectangle is altered by increasing its length by 20 percent and its width by 10 percent, its area increases by a percent. W
aleksklad [387]

Answer:

D

Step-by-step explanation:

Remember that the formula for the area of a rectangle is:

A=lw

Where l is the our length and w is our width.

If we increase our length by 20%, this means that we add 20% or 0.2 of our old length to our old length. So, our new length will be:

l_{new}=l+.2l

Combine like terms:

l_{new}=1.2l

Similarly, if we increase our width by 10%, this means that we add 10% or 0.1 of our old width to our old width. So, our new width is:

w_{new}=0.1w+w

Combine like terms:

w_{new}=1.1w

Therefore, our new area will be:

A_{new}=(l_{new})(w_{new})

Substitute 1.2l and 1.1w. This yields:

A_{new}=1.2l(1.1w)

Multiply:

A_{new}=1.32lw

Our old area is:

A_{old}=lw

So, our area increased by a factor of 1.32.

This is the same as 32% of our old area.

So, our answer is D.

And we're done!

5 0
3 years ago
Can 3.65909090909 be expressed as a fraction whose denominator is a power of 10? Explain.
GuDViN [60]
\bf 3.659\textit{ can also be written as }\cfrac{3659}{1000}\textit{ therefore }3.6590909\overline{09}\\\\&#10;\textit{can be written as }\cfrac{3659.0909\overline{09}}{1000}

notice above, all we did, was isolate the "recurring part" to the right of the decimal point, so the repeating 09, ended up on the right of it.

now, let's say, "x" is a variable whose value is the recurring part, therefore then

\bf \cfrac{3659.0909\overline{09}}{1000}\qquad \boxed{x=0.0909\overline{09}} \qquad \cfrac{3659+0.0909\overline{09}}{1000}\implies \cfrac{3659+x}{1000}

now, the idea behind the recurring part is that, we then, once we have it all to the right of the dot, we multiply it by some power of 10, so that it moves it "once" to the left of it, well, the recurring part is 09, is two digits, so let's multiply it by 100 then, 

\bf \begin{array}{llllllll}&#10;100x&=&09.0909\overline{09}\\&#10;&&9+0.0909\overline{09}\\&#10;&&9+x&#10;\end{array}\quad \implies 100x=9+x\implies 99x=9&#10;\\\\\\&#10;x=\cfrac{9}{99}\implies \boxed{x=\cfrac{1}{11}}\\\\&#10;-------------------------------\\\\&#10;\cfrac{3659.0909\overline{09}}{1000}\qquad \boxed{x=0.0909\overline{09}} \quad \cfrac{3659+0.0909\overline{09}}{1000}\implies \cfrac{3659+x}{1000}&#10;\\\\\\&#10;\cfrac{3659+\frac{1}{11}}{1000}

and you can check that in your calculator.
8 0
4 years ago
HELP ASAP PLEASE WILL MARK BRAINIEST
allsm [11]
It has to be 45 degrees pal
6 0
3 years ago
Write 2.14 in word form
Vesna [10]

Answer:

two dollars and fourteen cents

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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