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Monica [59]
3 years ago
12

Appease answer ill do anything please

Mathematics
2 answers:
lana66690 [7]3 years ago
6 0

Answer:

y=x+50

Step-by-step explanation:

liberstina [14]3 years ago
5 0

Answer:

y=50x

Step-by-step explanation:

distance = 50 times the laps

100= 50 x 2

200 = 50 x 4

250= 50 x 5

400 = 50 x 8

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List a value of b that will cause 4x2 + bx + 25 = 0 to have one real solution
vlada-n [284]

Answer:

20

Step-by-step explanation:

If you take (2x+5) (2x+5) = 0

then 4x^2 + 20x +25 = 0

5 0
3 years ago
I kinda need this now :/ Help pls, Will give brainlist**
sertanlavr [38]

Answer:

Answer:

you said you needed 22,23

22. y=7x-6

23. y=-x

Step-by-step explanation:

use math-way to put in the points

it explains for you

Step-by-step explanation:

6 0
3 years ago
Helppp plsssss!! Asap<br><br>Thanks
lubasha [3.4K]

Answer:

Ithink the answers B

Step-by-step explanation:

I think this because its even


3 0
3 years ago
Type SSS, SAS, ASA, SAA, or HL<br><br> To justify why the two larger triangles are<br> Congruent.
lakkis [162]
I’m assuming the answer is HL since they only gave us two letters.
6 0
3 years ago
The following integral requires a preliminary step such as long division or a change of variables before using the method of par
shtirl [24]

Division yields

\dfrac{x^4+7}{x^3+2x} = x-\dfrac{2x^2-7}{x^3+2x}

Now for partial fractions: you're looking for constants <em>a</em>, <em>b</em>, and <em>c</em> such that

\dfrac{2x^2-7}{x(x^2+2)} = \dfrac ax + \dfrac{bx+c}{x^2+2}

\implies 2x^2 - 7 = a(x^2+2) + (bx+c)x = (a+b)x^2+cx + 2a

which gives <em>a</em> + <em>b</em> = 2, <em>c</em> = 0, and 2<em>a</em> = -7, so that <em>a</em> = -7/2 and <em>b</em> = 11/2. Then

\dfrac{2x^2-7}{x(x^2+2)} = -\dfrac7{2x} + \dfrac{11x}{2(x^2+2)}

Now, in the integral we get

\displaystyle\int\frac{x^4+7}{x^3+2x}\,\mathrm dx = \int\left(x+\frac7{2x} - \frac{11x}{2(x^2+2)}\right)\,\mathrm dx

The first two terms are trivial to integrate. For the third, substitute <em>y</em> = <em>x</em> ² + 2 and d<em>y</em> = 2<em>x</em> d<em>x</em> to get

\displaystyle \int x\,\mathrm dx + \frac72\int\frac{\mathrm dx}x - \frac{11}4 \int\frac{\mathrm dy}y \\\\ =\displaystyle \frac{x^2}2+\frac72\ln|x|-\frac{11}4\ln|y| + C \\\\ =\displaystyle \boxed{\frac{x^2}2 + \frac72\ln|x| - \frac{11}4 \ln(x^2+2) + C}

7 0
2 years ago
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