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Monica [59]
3 years ago
12

Appease answer ill do anything please

Mathematics
2 answers:
lana66690 [7]3 years ago
6 0

Answer:

y=x+50

Step-by-step explanation:

liberstina [14]3 years ago
5 0

Answer:

y=50x

Step-by-step explanation:

distance = 50 times the laps

100= 50 x 2

200 = 50 x 4

250= 50 x 5

400 = 50 x 8

You might be interested in
A town has a population of 12000 and grows at 4% every year. To the nearest tenth of a year, how long will it be until the popul
ch4aika [34]

Answer:

  11.0 years

Step-by-step explanation:

The exponential function describing the population growth can be written ...

  population = (initial population)×(1 +growth rate)^years

If t represents the number of years, we can fill in the values to get ...

  18500 = 12000×1.04^t

Dividing by 12000 gives ...

  18500/12000 = 1.04^t

Taking logarithms, we have ...

  log(18500/12000) = t×log(1.04)

  t = log(185/120)/log(1.04) ≈ 11.037 ≈ 11.0

It will be 11.0 years until the population reaches 18,500.

7 0
3 years ago
Given:
Fynjy0 [20]

Answer:

Option B is correct.

\triangle RST \cong \triangle TUR  

Step-by-step explanation:

Given: RSTU is a parallelogram.

By definition of parallelogram, two pairs of opposite sides are congruent in length.

⇒TU \cong RS and TS \cong RU

In triangle RST and  triangle TUR

RS \cong TU  [Side]  

TS \cong RU  [Side]

RT \cong RT   [Common side]

SSS(Side-Side-Side) postulates states that if three sides of one triangle are congruent to three sides of other triangle, then the triangles are congruent.

then, by SSS postulates we have;

\triangle RST \cong \triangle TUR    


5 0
3 years ago
Decimals between 10 15 with an interval of 0.75 between each pair of decimals
aleksley [76]
Should be <span>10.75, 11.5, 12.25, 13, 13.75, 14.5</span>
5 0
3 years ago
Read 2 more answers
Xian plans to run 14 laps around a track, each lap is 400 yards which would make his run a total of 5600 yards. So far Xian has
k0ka [10]

Answer:

4.2 laps

Step-by-step explanation:

because 4 laps is 1600+ the 80 which is a 1/5 of 400 causing it to be .2

6 0
2 years ago
The average yield of the standard variety off soybeans per acre on a farm in a region is 48.8 bushels per acre, with a standard
I am Lyosha [343]

Answer:

z=\frac{53.4-48.8}{\frac{12}{\sqrt{36}}}=2.3  

p_v =P(Z>2.3)=1-P(Z  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true mean is not significantly higher than 48.8 at 1% of signficance.  

Step-by-step explanation:

1) Data given and notation  

\bar X=53.4 represent the sample mean

\sigma=12 represent the population standard deviation assumed

n=36 sample size  

\mu_o =48.8 represent the value that we want to test  

\alpha=0.01 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

2) State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean is higher than 48.8, the system of hypothesis would be:  

Null hypothesis:\mu \leq 48  

Alternative hypothesis:\mu > 48  

Since we assume that know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

3) Calculate the statistic  

We can replace in formula (1) the info given like this:  

z=\frac{53.4-48.8}{\frac{12}{\sqrt{36}}}=2.3  

4)P-value  

Since is a right tailed test the p value would be:  

p_v =P(Z>2.3)=1-P(Z  

5) Conclusion  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true mean is not significantly higher than 48.8 at 1% of signficance.  

3 0
3 years ago
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