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Whitepunk [10]
3 years ago
12

What are village by laws​

Computers and Technology
1 answer:
melomori [17]3 years ago
4 0

Explanation:

LAWS have long been familiar to the student of the English village. these regulations dealt mai ly with the open-field husbandry and pasture rights of ....

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Care should be taken whenever you post comments or photos to any social media or other websites, because each of these online ac
REY [17]

Answer:

True

Explanation:

Building your personal brand requires extreme care when it comes to social media presence. In the age of internet there is nothing hidden, so whatever you post or comment will be seen by your audience and it can go in either way. It can either make your brand or break it. It is of utmost importance to leave a pleasant and positive impact on your audience. One should not indulge in inappropriate or controversial debates and try to avoid being too personal on social media.  

6 0
4 years ago
Edward scissorhands Of course, Jim is the villain, but who or what is the antagonist in the film? Explain in detail.
Doss [256]
Jim is the main antagonist while Edward is the main protagonist of the movie.
8 0
2 years ago
Write a program that will read in a line of text and output the number of words in the line and the number of occurrences of eac
kherson [118]

Answer:

Here is the C++ program:

#include<iostream>  //to use input output functions

#include <algorithm>  //to use tolower() function

using namespace std;  //to identify objects like cin cout

int main() {  //start of main function

 string text;  // to hold text input

 cout<<"Enter a line of text: ";  // prompts user to enter a string

 getline(cin,text);  // reads the input string (text) from user

transform(text.begin(), text.end(), text.begin(), ::tolower);  //converts the text into lower case

 int letter[26] = {0}; //to hold the letters

 int i;  // used as a loop variable

 int words=0;  // to hold the count of words

 for(i = 0; i< text.size();i++){  // iterates through the text

 if(isalpha(text[i])&&(text[i+1]=='.'||text[i+1]==','||text[i+1]==' '))  //checks if the character at i-th index of text is a letter, and checks if i+1 index position of text is a period, comma or a space

 words++;  // adds 1 to the count of words

 if(isalpha(text[i]))  // if the character at the i-th index of text is a letter

 letter[text[i]-'a']++;  }  // counts the occurrences of each letter

 char j = text[text.size()-1];  // sets j to the last character of text

 if(j != '.' && j!= ' '&& j!=',' &&j!= '\0')  //if the last character is not a period or empty space  or comma or end of lone

 words++;  //add 1 to the count of words

 cout<<"Number of words: "<<words<<endl;  //display the number of words in the text

 for(i=0; i<26; i++)  {  //iterates 25 times

   if(letter[i]>0)  //if letter at index i is greater than 0

   cout<<(char)('a'+i)<<" : "<<letter[i]<<endl;  }} //displays each letters and its number of occurrences in the text

 

Explanation:

The program is explained in the attached document with an example.

7 0
4 years ago
. Explain how semaphores are handled in embedded systems design
Readme [11.4K]

Answer:

 Semaphores carries the signal between the task and interrupts that does not carry any type of additional data in the embedded system. A semaphore is used as synchronization object and helps in maintain the value between zero and the specific higher value.  

It basically reduced the value each time and complete the semaphore object in the embedded system. Binary semaphores is the main type of semaphore that invoke activation of the task.

 

5 0
3 years ago
A router receives a packet and determines the outbound link for the packet. When the packet arrives, 2/3 of one other packet is
vlada-n [284]

Answer:

Queuing Delay is 0.08 seconds

Explanation:

The answer follows a formula that is relatively easy to use and is detailed below.

Queuing Delay = [(L - x) + (nL)] / R

where,

L is packet length given as 3,000 bytes

x is the currently transmitted packet given as 2/3 * 3,000 = 2,000

n is the number of packets waiting in the Que given as 5

R is the rate of transmission given as 4 Mbps (4 * 10^6 Bps)

We can simply plug in the above information in the equation for computing Queuing Delay.

Lets take the numerator first which would be [(3000 - 2000) + (5 * 3000)]

The numerator would be 16000 bytes. These are being transmitted at 4Mbps. So, 16000*4*5 = 320,000 "bits"

Queuing Delay= 320,000/4000000

Queuing Delay = 0.08 seconds.

As we can see, the formula is quite intuitive to use. You are simply taking the number of packets to be transmitting, incorporating the partially transmitted packet, multiplying by the number of packets and the rate of transmission and then dividing the product by the rate of transmission to compute what the delay in the Que is.

6 0
3 years ago
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