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3 years ago

What is word processing and word wrap?

1 answer:

8 0

MARK ME BRAINLIEST

1. Sometimes referred to as a run around, word wrap is a feature in text editors and word processors that moves to the next line when reaching the end without requiring you to press Enter. For example, in the picture below you can see as each section is shrunk the sentence is wrapped, so it does not extend past the border. You can see a live example of how text wraps by resizing the browser window on this page.

2. word proc·ess·ing

the production, storage, and manipulation of text on a computer or word processor.

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Oxnard Casualty wants to ensure that their e-mail server has 99.98 percent reliability. They will use several independent server

sattari [20]

Answer:

The smallest number of servers required is 3 servers

Explanation:

Given

$Reliability = 99.98\%$

$Individual Servers = 95\%$

Required

Minimum number of servers needed

Let p represent the probability that a server is reliable and the probability that it wont be reliable be represented with q

Such that

$p = 95\%\\$

It should be noted that probabilities always add up to 1;

So,

$p + q = 1$ '

Subtract p from both sides

$p - p + q = 1 - p$

$q = 1 - p$

Substitute $p = 95\%\\$

$q = 1 - 95\%$

Convert % to fraction

$q = 1 - \frac{95}{100}$

Convert fraction to decimal

$q = 1 - 0.95$

$q = 0.05$

------------------------------------------------------------------------------------------------

To get an expression for one server

The probabilities of 1 servers having 99.98% reliability is as follows;

$p = 99.98\%$

Recall that probabilities always add up to 1;

So,

$p + q = 1$

Subtract q from both sides

$p + q - q = 1 - q$

$p = 1 - q$

So,

$p = 1 - q = 99.98\%$

$1 - q = 99.98\%$

Let the number of servers be represented with n

The above expression becomes

$1 - q^n = 99.98\%$

Convert percent to fraction

$1 - q^n = \frac{9998}{10000}$

Convert fraction to decimal

$1 - q^n = 0.9998$

Add $q^n$ to both sides

$1 - q^n + q^n= 0.9998 + q^n$

$1 = 0.9998 + q^n$

Subtract 0.9998 from both sides

$1 - 0.9998 = 0.9998 - 0.9998 + q^n$

$1 - 0.9998 = q^n$

$0.0002 = q^n$

Recall that $q = 0.05$

So, the expression becomes

$0.0002 = 0.05^n$

Take Log of both sides

$Log(0.0002) = Log(0.05^n)$

From laws of logarithm $Loga^b = bLoga$

So,

$Log(0.0002) = Log(0.05^n)$ becomes

$Log(0.0002) = nLog(0.05)$

Divide both sides by $Log0.05$

$\frac{Log(0.0002)}{Log(0.05)} = \frac{nLog(0.05)}{Log(0.05)}$

$\frac{Log(0.0002)}{Log(0.05)} = n$

$n = \frac{Log(0.0002)}{Log(0.05)}$

$n = \frac{-3.69897000434}{-1.30102999566}$

$n = 2.84310893421$

$n = 3 (Approximated)$

Hence, the smallest number of servers required is 3 servers

6 0

2 years ago

Describe the function of the user account section of the control panel

cluponka [151]

From Google:

"User Account Control or UAC for short is a security feature of Windows which helps prevent unauthorized changes to the operating system. These changes can be initiated by applications, users, viruses or other forms of malware."

6 0

3 years ago

Professor Gig A. Byte needs to store text made up of the characters A with frequency 6, B with frequency 2, C with frequency 3,

Luden [163]

Answer:

This is not true

Explanation:

The optimal Huffman code is used to encrypt and compress text files. It uses fixed-length code or variable-length code for encryption and compression of data.

The professor's character code is similar to Huffman's variable-length coding which uses variable length od binary digits to represent the word strings. The file size of the text file above is;

= 6 x 1 + 2 x 2 + 3 x 2 + 2 x 2 + 8 x 1 = 28 bits

This would be the same for both cases.

The encrypt would be the problem as the encoded and decoding of the characters B and E may cause an error.

8 0

2 years ago

____ are the in-house equivalent of Internet newsgroups. They use Web- or software-based discussion tools that are available acr

antiseptic1488 [7]

The correct answer is Intranet chat rooms

8 0

2 years ago

Which command displays the status of the ipsec installation?

Alexandra [31]

Character command shows the status.

8 0

2 years ago